python - 从 Airflow Postgres Hook 中检索完整连接 URI

Question

有没有更简洁的方法从 Postgres 钩子(Hook)中获取完整的 URI？ .get_uri()不包括“额外”参数，所以我像这样附加它们:

def pg_conn_id_to_uri(postgres_conn_id):
    hook = PostgresHook(postgres_conn_id)
    uri = hook.get_uri()

    extra = hook.get_connection(postgres_conn_id).extra_dejson
    params = [ f'{k}={v}' for k, v in extra.items() ]

    if params:
        params = '&'.join(params)
        uri += f'?{params}'

    return uri

Answer 1

如果清洁剂在这里并不一定意味着简洁，那么这里可能会起作用

from typing import Dict, Any

from psycopg2 import extensions

from airflow.hooks.postgres_hook import PostgresHook
from airflow.models.connection import Connection


def pg_conn_id_to_uri(postgres_conn_id: str) -> str:
    # create hook & conn
    hook: PostgresHook = PostgresHook(postgres_conn_id=postgres_conn_id)
    conn: Connection = hook.get_connection(conn_id=postgres_conn_id)
    # retrieve conn_args & extras
    extras: Dict[str, Any] = conn.extra_dejson
    conn_args: Dict[str, Any] = dict(
        host=conn.host,
        user=conn.login,
        password=conn.password,
        dbname=conn.schema,
        port=conn.port)
    conn_args_with_extras: Dict[str, Any] = {**conn_args, **extras}
    # build and return string
    conn_string: str = extensions.make_dsn(dsn=None, **conn_args_with_extras)
    return conn_string

请注意，该片段未经测试

当然，我们仍然可以从这里剪掉更多的行(例如，通过使用 python 的语法糖 conn.__dict__.items() )，但我更喜欢清晰而不是简洁

提示来自 Airflow的 & pyscopg2的代码本身

PostgresHook

pyscopg2