c - 我应该修复什么才能在此代码中创建随机计算？

Question

我想修复我的代码以在此处创建随机操作，我应该在此处修复什么？

    #include <stdio.h>

    int main()
    {
        int x,y,z,a;
        char o;
        while(1)
        {
            printf("give your three numbers: ");
            scanf("%d %d %d",&x,&y,&z);
            printf("(%d*%d-%d) what is the correct among following answers? \n 1. %d\n 2. %d\n 3. %d\n ", 
            x,y,z,x*y-z,x*y*z,x-y*z);
            printf("what is answer? \n: ");
            scanf("%d",&a);
            if(a == 1)
            {
                printf("you are right!\n");
            }
            else
            {
                printf("you are false!\n\n");
            }

            getchar();
            printf("Would you like to exit programm? (y/n) : ");
            scanf("%c",&o);
            if (o=='Y' || o=='y')
            {
                break;
            }
            else if(o=='N' || o=='n')
            {
                continue;
            }
            else
            {
                printf("Wrong input!!!!");
            }
            return 0;
        }
    }

我的意思是我想在运行代码时随机尝试更改操作，例如 * + - 并且连同这个问题，答案应该更改......谢谢!

Answer 1

你的问题主要集中在洗牌答案上。通过从几个站点进行研究，我找到了解决方案。这个有点难，多看几次代码就可以搞定

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void swap(int *a, int *b) {
    int temp = *a;
    *a = *b;
    *b = temp;
}

void randomize(int arr[], int n) {
    srand(time(NULL));
    int i;
    for(i = n-1; i > 0; i--) {
        int j = rand() % (i+1);
        swap(&arr[i], &arr[j]);
    }
}

int main() {
    int x,y,z,a;
    int i;
    int a1, a2, a3;
    int arr[] = {1, 2, 3};
    int n = sizeof(arr)/ sizeof(arr[0]);

    printf("give your three numbers: ");
    scanf("%d %d %d",&x,&y,&z);

    a1 = x*y-z;
    a2 = x*y*z;
    a3 = x-y*z;

    printf("Before shuffle = %d %d %d\n\n", a1, a2, a3);

    char answers[] = {a1, a2, a3};

    printf("(%d*%d-%d)what is the correct among following answers?\n", x, y, z);

    randomize (arr, n);
    for(i=0; i<n; i++) {
        int index = arr[i];
        printf("%2d - %d\n", i+1, answers[index]);
    }

    return 0;
}

这是输出

第一次运行

give your three numbers: 2
2
2
Before shuffle = 2 8 -2

(2*2-2)what is the correct among following answers?
 1 - 8
 2 - 2
 3 - -2

第二次运行

give your three numbers: 2
2
2
Before shuffle = 2 8 -2

(2*2-2)what is the correct among following answers?
 1 - -2
 2 - 8
 3 - 2

您可以多次尝试。每次答案都会被洗牌。这是Source我已经提到了。