django - Django过滤器返回将在模板中呈现的HTML

Question

my_text

my_text = '''The template system works in a two-step process: compiling and rendering. A compiled template is, simply, a list of Node objects.

Thus, to define a custom template tag, you specify how the raw template tag is converted into a Node (the compilation function), and what the node’s render() method does.'''

my_filter

@register.filter(is_safe=True)
def format_description(description):
    text = ''
    for i in description.split('\n'):
        text += ('<p class="site-description">' + i + '</p>')
    return text

我的问题

我像这样在原始html中获得输出

 <p class="site-description">The template system works in a two-step process: compiling and rendering. A compiled template is, simply, a list of Node objects.</p><p class="site-description">    </p><p class="site-description">    Thus, to define a custom template tag, you specify how the raw template tag is converted into a Node (the compilation function), and what the node’s render() method does.</p>

代替

The template system works in a two-step process: compiling and rendering. A compiled template is, simply, a list of Node objects.

Thus, to define a custom template tag, you specify how the raw template tag is converted into a Node (the compilation function), and what the node’s render() method does.

这个主意

想法是获取文本并为拆分后创建的列表的每个部分创建不同的段落，以便可以将文本格式化为漂亮的
和密封性

Answer 1

要禁用自动转义，可以使用 mark_safe 方法:

from django.utils.safestring import mark_safe

@register.filter(is_safe=True)
def format_description(description):
    text = ''
    for i in description.split('\n'):
        text += ('<p class="site-description">' + i + '</p>')
    return mark_safe(text)