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rest - 如何使用JAX-RS进行身份验证

转载 作者:行者123 更新时间:2023-12-04 04:08:08 25 4
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我正在寻找有关如何保护我的剩余根资源的一些建议

@Path("/employee")
public class EmployeeResource {

@GET
@Produces("text/html")
public String get(
@QueryParam("name") String empname,
@QueryParam("sn") String sn) {

// Return a data back.
}
}

我已经阅读了有关基本认证和OAuth的文章,我知道这个概念,但是我正在寻找有关如何在代码中实现它的方法。

谢谢

最佳答案

声明一个拦截器:

 <bean id="securityInterceptor" class="AuthenticatorInterceptor">
<property name="users">
<map>
<entry key="someuser" value="somepassword"/>
</map>
</property>

然后使用它:
  <jaxrs:server address="/">
<jaxrs:inInterceptors>
<ref bean="securityInterceptor"/>
</jaxrs:inInterceptors>
(etc)

然后是您的AuthenticationInterceptor,大致如下:
import java.util.Map;

import org.apache.cxf.message.Message;
import org.apache.cxf.phase.PhaseInterceptor;
import org.apache.cxf.phase.AbstractPhaseInterceptor;
import org.apache.cxf.phase.Phase;
import org.apache.cxf.configuration.security.AuthorizationPolicy;
import org.apache.cxf.interceptor.Interceptor;

import org.springframework.beans.factory.annotation.Required;

public class AuthenticatorInterceptor extends AbstractPhaseInterceptor<Message> {

private Map<String,String> users;

@Required
public void setUsers(Map<String, String> users) {
this.users = users;
}

public AuthenticatorInterceptor() {
super(Phase.RECEIVE);
}

public void handleMessage(Message message) {

AuthorizationPolicy policy = message.get(AuthorizationPolicy.class);

if (policy == null) {
System.out.println("User attempted to log in with no credentials");
throw new RuntimeException("Denied");
}

String expectedPassword = users.get(policy.getUserName());
if (expectedPassword == null || !expectedPassword.equals(policy.getPassword())) {
throw new RuntimeException("Denied");
}
}

}

读者可以以更方便的方式定义可接受的凭据。

关于rest - 如何使用JAX-RS进行身份验证,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4124831/

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