python - 这行代码使程序对重启功能无 react

Question

我尝试用 Python 编写一个程序，让用户对其中一只 turtle 下注，赛后告诉他是否正确。我想让用户选择是否要通过单击“r”来重新开始比赛 - (我使用了 turtle.onkey 方法)并且在我输入这行代码之前它工作正常:bet = screen.textinput("选择你的赌注"，"输入蓝色或绿色:")。现在该程序让用户可以像我想要的那样选择他的赌注，但是当按下“r”时它不会使用react..我想澄清的是，在 textinput 代码行之后，程序不会对任何 .onkey 方法使用react。有人知道为什么会这样吗？

代码:

import turtle
import random
import ctypes

speed = random.randint(0, 2)

myTurtle = turtle.Turtle()
myTurtle2 = turtle.Turtle()
screen = turtle.Screen()
def up():
    myTurtle.setheading(90)
    myTurtle.forward(10)

def down():
    myTurtle.setheading(270)
    myTurtle.forward(10)

def left():
    myTurtle.setheading(180)
    myTurtle.forward(10)

def right():
    myTurtle.setheading(0)
    myTurtle.forward(10)

def up2():
    myTurtle2.setheading(90)
    myTurtle2.forward(10)

def down2():
    myTurtle2.setheading(270)
    myTurtle2.forward(10)

def left2():
    myTurtle2.setheading(180)
    myTurtle2.forward(10)

def right2():
    myTurtle2.setheading(0)
    myTurtle2.forward(10)

def restart():
    myTurtle.setposition(400, -300)
    myTurtle.setheading(90)
    myTurtle2.setposition(-400, -300)
    myTurtle2.setheading(90)
    speed = random.randint(0, 2)
    bet = screen.textinput("Choose your bet", "Enter blue or green: ")
    while myTurtle.ycor() < 300 and myTurtle2.ycor() < 300:
        if speed == 1:
            up()
        elif speed == 2:
            up2()
        speed = random.randint(0, 2)
    if myTurtle.ycor() == 300:
        if bet == "blue":
            ctypes.windll.user32.MessageBoxW(0, "Blue is the winner", "You win!", 0x00010000)
        else:
            ctypes.windll.user32.MessageBoxW(0, "Blue is the winner", "You lost", 0x00010000)
    else:
        if bet == "green":
            ctypes.windll.user32.MessageBoxW(0, "Green is the winner", "You win!", 0x00010000)
        else:
            ctypes.windll.user32.MessageBoxW(0, "Green is the winner", "You lost", 0x00010000)

screen.title("Turtle race")
turtle.listen()
myTurtle.shape("turtle")
myTurtle2.shape("turtle")
myTurtle.setposition(400,-300)
myTurtle.setheading(90)
myTurtle2.setposition(-400,-300)
myTurtle2.setheading(90)
myTurtle.dot(10, "blue")
myTurtle2.dot(10, "green")
myTurtle.pencolor("blue")
myTurtle2.pencolor("green")

myTurtle.speed(0)
myTurtle2.speed(0)
bet = screen.textinput("Choose your bet", "Enter blue or green: ")
while myTurtle.ycor() < 300 and myTurtle2.ycor() < 300:
    if speed == 1:
        up()
    elif speed == 2:
        up2()
    speed = random.randint(0, 2)

if myTurtle.ycor() == 300:
    if bet == "blue":
        ctypes.windll.user32.MessageBoxW(0, "Blue is the winner", "You win!", 0x00010000)
    else:
        ctypes.windll.user32.MessageBoxW(0, "Blue is the winner", "You lost", 0x00010000)
else:
    if bet == "green":
        ctypes.windll.user32.MessageBoxW(0, "Green is the winner", "You win!", 0x00010000)
    else:
        ctypes.windll.user32.MessageBoxW(0, "Green is the winner", "You lost", 0x00010000)



turtle.onkey(up, 'Up')
turtle.onkey(down, 'Down')
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')

turtle.onkey(restart, 'r')

turtle.onkey(up2, 'w')
turtle.onkey(down2, 's')
turtle.onkey(left2, 'a')
turtle.onkey(right2, 'd')
turtle.mainloop()

Answer 1

问题是 onkey 需要关注主窗 Eloquent 能从系统获取 key ，但是当您执行 textinput 时，这个焦点就会丢失，它需要 screen.listen () 再次。

---

最少的工作代码。

因为您在 restart() 内部和 restart() 外部重复了一些代码，所以我运行 restart() 而不是外部代码。

因为我不用Windows所以我用tkinter.messagebox来显示消息。 turtle 已经使用 tkinter 来显示带有 Canvas 和 textinput 的主窗口。

import turtle
import random
#import tkinter  as tk
from tkinter import messagebox

# functions ---

def up():
    myTurtle.setheading(90)
    myTurtle.forward(10)

def down():
    myTurtle.setheading(270)
    myTurtle.forward(10)

def left():
    myTurtle.setheading(180)
    myTurtle.forward(10)

def right():
    myTurtle.setheading(0)
    myTurtle.forward(10)

def up2():
    myTurtle2.setheading(90)
    myTurtle2.forward(10)

def down2():
    myTurtle2.setheading(270)
    myTurtle2.forward(10)

def left2():
    myTurtle2.setheading(180)
    myTurtle2.forward(10)

def right2():
    myTurtle2.setheading(0)
    myTurtle2.forward(10)

def restart():
    myTurtle.setposition(400, -300)
    myTurtle.setheading(90)
    myTurtle2.setposition(-400, -300)
    myTurtle2.setheading(90)
    
    speed = random.randint(0, 2)
    bet = screen.textinput("Choose your bet", "Enter blue or green: ")

    screen.listen()  # <--- set focus on main window after `textinput`
    
    while myTurtle.ycor() < 300 and myTurtle2.ycor() < 300:
        if speed == 1:
            up()
        elif speed == 2:
            up2()
        speed = random.randint(0, 2)

    if myTurtle.ycor() == 300:
        if bet == "blue":
            messagebox.showinfo("Result", "Blue is the winner\n\nYou win!")
        else:
            messagebox.showinfo("Result", "Blue is the winner\n\nYou lost")
    else:
        if bet == "green":
            messagebox.showinfo("Result", "Green is the winner\n\nYou win!")
        else:
            messagebox.showinfo("Result", "Green is the winner\n\nYou lost")
    
# --- main ---

speed = random.randint(0, 2)

myTurtle  = turtle.Turtle()
myTurtle2 = turtle.Turtle()

screen = turtle.Screen()
screen.title("Turtle race")

myTurtle.shape("turtle")
myTurtle2.shape("turtle")

turtle.onkey(up, 'Up')
turtle.onkey(down, 'Down')
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')

turtle.onkey(restart, 'r')

turtle.onkey(up2, 'w')
turtle.onkey(down2, 's')
turtle.onkey(left2, 'a')
turtle.onkey(right2, 'd')

restart()

turtle.mainloop()

---

编辑:

减少代码 - 我将 turtle 放在列表中，稍后我可以使用 myTurtles[number] 并且我可以使用一个函数 up(number) 而不是两个函数 up() 和 up2()

import turtle
import random
from tkinter import messagebox

# functions ---

def up(number):
    myTurtles[number].setheading(90)
    myTurtles[number].forward(10)

def down(number):
    myTurtles[number].setheading(270)
    myTurtles[number].forward(10)

def left(number):
    myTurtles[number].setheading(180)
    myTurtles[number].forward(10)

def right(number):
    myTurtles[number].setheading(0)
    myTurtles[number].forward(10)

def restart():
   
    myTurtles[0].setposition(400, -300)
    myTurtles[0].setheading(90)
    myTurtles[1].setposition(-400, -300)
    myTurtles[1].setheading(90)
    
    bet = screen.textinput("Choose your bet", "Enter blue or green: ")
    screen.listen()
    
    speed = random.randint(0, 2)
    while myTurtles[0].ycor() < 300 and myTurtles[0].ycor() < 300:
        if speed < 2: # randint(0, 2) can gives 0, 1, 2  
            up(speed)
        speed = random.randint(0, 2)

    if myTurtles[0].ycor() == 300:
        if bet == "blue":
            messagebox.showinfo("Result", "Blue is the winner\n\nYou win!")
        else:
            messagebox.showinfo("Result", "Blue is the winner\n\nYou lost")
    else:
        if bet == "green":
            messagebox.showinfo("Result", "Green is the winner\n\nYou win!")
        else:
            messagebox.showinfo("Result", "Green is the winner\n\nYou lost")
    
# --- main ---

screen = turtle.Screen()
screen.title("Turtle race")

myTurtles = [
    turtle.Turtle(),
    turtle.Turtle(),
]    

myTurtles[0].shape("turtle")
myTurtles[1].shape("turtle")

turtle.onkey(lambda: up(0),    'Up')
turtle.onkey(lambda: down(0),  'Down')
turtle.onkey(lambda: left(0),  'Left')
turtle.onkey(lambda: right(0), 'Right')

turtle.onkey(lambda: up(1),    'w')
turtle.onkey(lambda: down(1),  's')
turtle.onkey(lambda: left(1),  'a')
turtle.onkey(lambda: right(1), 'd')

turtle.onkey(restart, 'r')

restart()

turtle.mainloop()