string - 我应该如何从 clojure 中的惰性序列创建一个字符串？

Question

我一直使用 str 来构造字符串:

user> (str '(1 2 3) " == " '(1 2 3))
"(1 2 3) == (1 2 3)"

我的屁股大约每天被咬一次:

user> (str '(1 2 3) " == " (map identity '(1 2 3)))
"(1 2 3) == clojure.lang.LazySeq@7861"

我想我可以说:

user> (with-out-str (print '(1 2 3) " == " (map identity '(1 2 3))))
"(1 2 3)  ==  (1 2 3)"

相反，但看起来很难看。有没有更好的办法？

Answer 1

你可以使用print-str:

(print-str '(1 2 3) " == " (map identity '(1 2 3)))
;; => "(1 2 3) == (1 2 3)"