java - SurfaceView同时显示两个动画

Question

我正在尝试让两个动画同时显示。应用程序构建成功但在模拟器中崩溃。

我在线程中创建了一个 Anim 类，该类在 while 循环中处理动画。我认为我的绘制方法有问题，但我似乎无法弄清楚。

我很感激任何帮助，谢谢

错误日志

java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.myproject/com.example.myproject.MainActivity}: java.lang.IllegalArgumentException: Cannot add a null child view to a ViewGroup

和

java.lang.ArrayIndexOutOfBoundsException: length=2; index=2
        at com.example.my_project.PlayActivity$surfaceView$Anim.run(PlayActivity.java:109)

代码

public class PlayActivity extends AppCompatActivity {
surfaceView view;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    view = new surfaceView(this);

    setContentView(view);



public class surfaceView extends SurfaceView {


    public surfaceView(Context context) {
        super(context);
        new Anim().start();
    }


    private class Anim extends Thread {
        int counter = 0;
        int counter2 = 0;



        @Override
        public void run() {
            long last_updated_time = 0;
            long delay = 250;
            int[] purple_bird = {
                    R.drawable.bird1,
                    R.drawable.bird2
            };
            int[] red_bird = {
                    R.drawable.red1,
                    R.drawable.red2,
                    R.drawable.red3,
                    R.drawable.red4
            };


            while (true) {
                boolean playing = true;
                if (playing) {

                    long current_time = System.currentTimeMillis();
                    if (current_time > last_updated_time + delay) {
                        if ((counter >= 2) && (counter2 >= 4)) {
                            counter = 0;
                            counter2 = 0;


                        }
                        draw(purple_bird[counter], red_bird[counter2]);

                        last_updated_time = current_time;
                        counter++;
                        counter2++;
                    }
                }
            }




        }

        private void draw(int red_bird, int purple_bird) {

            SurfaceHolder holder = getHolder();
            Canvas canvas = holder.lockCanvas();

            if (canvas != null) {
                canvas.drawColor(Color.WHITE);
                Paint paint = new Paint();

                Bitmap purpleBird = BitmapFactory.decodeResource(getContext().getResources(), purple_bird);
                Bitmap redBird = BitmapFactory.decodeResource(getContext().getResources(), red_bird);


                Bitmap resizedRedBird = Bitmap.createScaledBitmap(redBird, (int) (redBird.getWidth() * 0.4), (int) (redBird.getHeight() * 0.4), true);
                Bitmap resizedPurpleBird = Bitmap.createScaledBitmap(purpleBird, (int) (purpleBird.getWidth() * 0.2), (int) (purpleBird.getHeight() * 0.2), true);

                canvas.drawBitmap(resizedRedBird, 500, 500, paint);
                canvas.drawBitmap(resizedPurpleBird, 100, 100, paint);

                holder.unlockCanvasAndPost(canvas);




            }

        }
    }





}

Answer 1

因为访问 SurfaceView(使用 Canvas)是独占的，所以您不能同时对其进行绘制。

holder.lockCanvas();

(...) // the canvas is locked during this

holder.unlockCanvasAndPost(canvas);

因此，您可能的解决方案是在同一线程的同一绘制方法(在锁定和解锁之间)中操作和绘制红色小鸟和蓝色小鸟。

---

编辑

对于另一个错误2:

if ((counter >= 2) && (counter2 >= 4)) {
    counter = 0;
    counter2 = 0;
}

这个条件是错误的。因为只有当counter 和counter2 都超过时，它们才会被重置。它们应该分开:

if (counter >= 2) {
    counter = 0;
}
if (counter2 >= 4) {
    counter2 = 0;
}