javascript - 检查键/值对对象数组的简洁方法？

Question

查找下面数组中的每个字符串是否存在于数组中对象中的某个 id 的简短方法是什么？我知道我可以执行 for 循环，但如果我运行多个查找，它就会变得乏味。

下面的示例应该输出 false，因为一个匹配，一个不匹配。

var array1= [
'j2n4k2j3n42k3j4n',
'ln23jk4n2njknn2n'
]


var array2 = [
    {
        fruit:"banana"
        origin:"florida"
        id:"j2n4k2j3n42k3j4n"
    },
    {
        fruit:"peach"
        origin:"georgia"
        id:"l2nkj2n3k4bj"
    },
]

Answer 1

下面的代码输出一个 bool 值。如果所有 id 在 array2 中可用，则为真

var array1 = [
  'j2n4k2j3n42k3j4n',
  "l2nkj2n3k4bj",
  'ln23jk4n2njknn2n'
]


var array2 = [{
    fruit: "banana",
    origin: "florida",
    id: "j2n4k2j3n42k3j4n",
  },
  {
    fruit: "peach",
    origin: "georgia",
    id: "l2nkj2n3k4bj"
  },
]

const results = array1.every(id => array2.find(item => item.id === id))

console.log(results)

如果要查找找到/未找到哪个元素，请使用以下方法。它输出一个包含 bool 值的数组，并且与 array1 具有相同的计数。如果找到 id，则输出数组将在该数组位置包含 true。

var array1 = [
  'j2n4k2j3n42k3j4n',
  "l2nkj2n3k4bj",
  'ln23jk4n2njknn2n'
]


var array2 = [{
    fruit: "banana",
    origin: "florida",
    id: "j2n4k2j3n42k3j4n",
  },
  {
    fruit: "peach",
    origin: "georgia",
    id: "l2nkj2n3k4bj"
  },
]
// Initial approach which works
// const results = array1.map(id => Boolean(array2.find(item => item.id === id)));

// Another approached as suggested by VLAZ and Phong in comments.  `some` will check and return the boolean.

const results = array1.map(id => array2.some(item => item.id === id));

console.log(results)