objective-c - 使用 NSRegularExpression 从正则表达式中提取部分

Question

我想用 NSRegularExpression 提取字符串的一部分。

例如，我有这个字符串:

@"1   UIKit                               0x00540c89 -[UIApplication _callInitializationDelegatesForURL:payload:suspended:] + 1163";

我想提取“UIKit”、“0x00540c89”、“UIApplication”、“_callInitializationDelegatesForURL:payload:suspended:”和“1163”。

我做了正则表达式:

@"^[0-9]+\\s+[a-zA-Z]+\\s+0x[0-9a-zA-Z]+\\s+\\-\\s*\\[[a-zA-Z]+\\s+[_:a-zA-Z]+\\]\\s+\\+\\s+[0-9]+"

但是我不知道我该怎么做。这是可能的。

    NSString *origen = @"1   UIKit                               0x00540c89 -[UIApplication _callInitializationDelegatesForURL:payload:suspended:] + 1163";
    // Setup an NSError object to catch any failures
    NSError *error = NULL;
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"^[0-9]+\\s+[a-zA-Z]+\\s+0x[0-9a-zA-Z]+\\s+\\-\\s*\\[[a-zA-Z]+\\s+[_:a-zA-Z]+\\]\\s+\\+\\s+[0-9]+" 
                                                                           options:NSRegularExpressionCaseInsensitive 
                                                                             error:&error];
    // create an NSRange object using our regex object for the first match in the string
    NSRange rangeOfFirstMatch = [regex rangeOfFirstMatchInString:origen options:0 range:NSMakeRange(0, [origen length])];
    // check that our NSRange object is not equal to range of NSNotFound
    if (!NSEqualRanges(rangeOfFirstMatch, NSMakeRange(NSNotFound, 0))) {
        // Since we know that we found a match, get the substring from the parent string by using our NSRange object
        NSString *substringForFirstMatch = [origen substringWithRange:rangeOfFirstMatch];
        NSLog(@"Extracted: %@",substringForFirstMatch);
    }

Answer 1

试试这个:

NSCharacterSet *separatorSet = [NSCharacterSet characterSetWithCharactersInString:@" -[]+?.,"];
NSMutableArray *array = [origen  componentsSeparatedByCharactersInSet:separatorSet];
[array removeObject:@""];