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group-by - 使用 lodash/underscore 分组并求和

转载 作者:行者123 更新时间:2023-12-04 03:20:34 25 4
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我有以下数组:

var 数据 = [{
"用户名": "rahul.prajapati",
“名字”:“拉胡尔生主”,
“项目 key ”:“项目1”,
“小时”:5,
},
{
"用户名": "rahul.prajapati",
“名字”:“拉胡尔生主”,
“项目 key ”:“项目1”,
“小时”:7.5,
},
{
"用户名": "rahul.prajapati",
“名字”:“拉胡尔生主”,
“项目 key ”:“项目2”,
“小时”:8,
},
{
"用户名": "rahul.prajapati",
“名字”:“拉胡尔生主”,
“项目 key ”:“项目2”,
“小时”:7.5,
},
{
"用户名": "kishor.thakkar",
“名称”:“基绍尔塔卡”,
“项目 key ”:“项目2”,
“小时”:0.25,
},
{
"用户名": "kishor.thakkar",
“名称”:“基绍尔塔卡”,
“项目 key ”:“项目2”,
“小时”:0.25,
},
{
"用户名": "kishor.thakkar",
“名称”:“基绍尔塔卡”,
“项目 key ”:“项目3”,
“小时”:0.25,
},
{
"用户名": "kishor.thakkar",
“名称”:“基绍尔塔卡”,
“项目 key ”:“项目3”,
“小时”:1.5,
}
]

我需要下面的数组,我需要项目应该按“用户名”分组,每个数组都有一个“项目”数组,这个“项目”数组将按"projectKey"和相同projectKey 的小时数应该被添加

[{
"Name": "Rahul Prajapati",
"Username" "rahul.prajapati",
"PROJECTS":[
{
"ProjectKey" : "project1",
"Hours" : 12.5
},
{
"ProjectKey" : "project2",
"Hours" : 15.5
},
]
},
{
"Name": "Kishor Thakkar",
"Username" "kishor.thakkar",
"PROJECTS":[
{
"ProjectKey" : "project1",
"Hours" : 0.50
},
{
"ProjectKey" : "project2",
"Hours" : 1.75
},
]
}
]

是否可以通过 Lodash 实现。

请帮忙,我是lodash的新手

每个帮助都是可观的

最佳答案

这是一个使用 lodash 的解决方案,它被分解成不同的函数以使其更具可读性(我希望如此):

// function used to calculate the total - _.sumBy not available in old lodash
var totalHours = function(total, project){
return total + project.Hours;
}

// function to sum the hours for each project
var sumProjects = function(projects){
return {
Projectkey: projects[0].Projectkey,
Hours: _.reduce(projects, totalHours, 0)
}
}

// function to group the projects for each user
var groupProjects = function(projects){
return _.chain(projects)
.groupBy('Projectkey')
.map(sumProjects)
.value();
}

// first group by Username
var groups = _.groupBy(data, 'Username');

// now build what we want for each group
var result = _.map(groups, function(group){
return {
Name: group[0].Name,
Username: group[0].Username,
PROJECTS: groupProjects(group)
};
})

var data = [{
"Username": "rahul.prajapati",
"Name": "Rahul Prajapati",
"Projectkey": "project1",
"Hours": 5,
},
{
"Username": "rahul.prajapati",
"Name": "Rahul Prajapati",
"Projectkey": "project1",
"Hours": 7.5,
},
{
"Username": "rahul.prajapati",
"Name": "Rahul Prajapati",
"Projectkey": "project2",
"Hours": 8,
},
{
"Username": "rahul.prajapati",
"Name": "Rahul Prajapati",
"Projectkey": "project2",
"Hours": 7.5,
},
{
"Username": "kishor.thakkar",
"Name": "Kishor Thakkar",
"Projectkey": "project2",
"Hours": 0.25,
},
{
"Username": "kishor.thakkar",
"Name": "Kishor Thakkar",
"Projectkey": "project2",
"Hours": 0.25,
},
{
"Username": "kishor.thakkar",
"Name": "Kishor Thakkar",
"Projectkey": "project3",
"Hours": 0.25,
},
{
"Username": "kishor.thakkar",
"Name": "Kishor Thakkar",
"Projectkey": "project3",
"Hours": 1.5,
}
];

var groups = _.groupBy(data, 'Username');

var totalHours = function(total, project){
return total + project.Hours;
}

var sumProjects = function(projects){
return {
Projectkey: projects[0].Projectkey,
Hours: _.reduce(projects, totalHours, 0)
}
}

var groupProjects = function(projects){
return _.chain(projects)
.groupBy('Projectkey')
.map(sumProjects)
.value();
}

var result = _.map(groups, function(group){
return {
Name: group[0].Name,
Username: group[0].Username,
PROJECTS: groupProjects(group)
}
})

document.getElementById('result').textContent = JSON.stringify(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.14.0/lodash.min.js"></script>

<p>
<pre id="result"></pre>
</p>

关于group-by - 使用 lodash/underscore 分组并求和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38636854/

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