gpt4 book ai didi

iOS7 中的 UITableViewCell indexPath 崩溃

转载 作者:行者123 更新时间:2023-12-04 03:04:25 24 4
gpt4 key购买 nike

我有一个 UITableViewCellUITableViewController .
在我的单元格中,有一个按钮,当您单击它时会将您带到另一个 viewprepareforsegue .
prepareForSegue我这样做:

if ([[segue identifier] isEqualToString:@"MySegue"])
{
UITableViewCell *cell = (UITableViewCell*) [[sender superview] superview];
UITableView *table = (UITableView*)[[[sender superview] superview] superview];
NSIndexPath *indexPath = [table indexPathForCell:cell];
}

好的!一切都一直运作良好。但是现在我已经用 iOS7 升级了 xCode,当我点击单元格中的按钮时,一个错误出现在我面前,我不知道如何解决它:
[UITableViewCell indexPathForCell:]: unrecognized selector sent to instance 0x9e160b0
2013-09-20 16:30:44.427 MyApp[8212:a0b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UITableViewCell indexPathForCell:]: unrecognized selector sent to instance 0x9e160b0'
*** First throw call stack:
(
0 CoreFoundation 0x024475e4 __exceptionPreprocess + 180
1 libobjc.A.dylib 0x01a5d8b6 objc_exception_throw + 44
2 CoreFoundation 0x024e4903 -[NSObject(NSObject) doesNotRecognizeSelector:] + 275
3 CoreFoundation 0x0243790b ___forwarding___ + 1019
4 CoreFoundation 0x024374ee _CF_forwarding_prep_0 + 14
5 MyApp 0x0004bc01 -[NewsTableViewController prepareForSegue:sender:] + 3441
6 UIKit 0x00af69cc -[UIStoryboardSegueTemplate _perform:] + 156
7 UIKit 0x00af6a59 -[UIStoryboardSegueTemplate perform:] + 115
8 libobjc.A.dylib 0x01a6f874 -[NSObject performSelector:withObject:withObject:] + 77
9 UIKit 0x005c4c8c -[UIApplication sendAction:to:from:forEvent:] + 108
10 UIKit 0x005c4c18 -[UIApplication sendAction:toTarget:fromSender:forEvent:] + 61
11 UIKit 0x006bc6d9 -[UIControl sendAction:to:forEvent:] + 66
12 UIKit 0x006bca9c -[UIControl _sendActionsForEvents:withEvent:] + 577
13 UIKit 0x006bbd4b -[UIControl touchesEnded:withEvent:] + 641
14 UIKit 0x00936d7f _UIGestureRecognizerUpdate + 7166
15 UIKit 0x00601d4a -[UIWindow _sendGesturesForEvent:] + 1291
16 UIKit 0x00602c6a -[UIWindow sendEvent:] + 1030
17 UIKit 0x005d6a36 -[UIApplication sendEvent:] + 242
18 UIKit 0x005c0d9f _UIApplicationHandleEventQueue + 11421
19 CoreFoundation 0x023d08af __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 15
20 CoreFoundation 0x023d023b __CFRunLoopDoSources0 + 235
21 CoreFoundation 0x023ed30e __CFRunLoopRun + 910
22 CoreFoundation 0x023ecb33 CFRunLoopRunSpecific + 467
23 CoreFoundation 0x023ec94b CFRunLoopRunInMode + 123
24 GraphicsServices 0x032c89d7 GSEventRunModal + 192
25 GraphicsServices 0x032c87fe GSEventRun + 104
26 UIKit 0x005c394b UIApplicationMain + 1225
27 MyApp 0x00002cfb main + 235
28 libdyld.dylib 0x01f42725 start + 0
29 ??? 0x00000001 0x0 + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException

应用程序崩溃的那一行是:
    NSIndexPath *indexPath = [table indexPathForCell:cell]; }

最佳答案

在 iOS7 UITableViewWrapperViewUITableViewCell的 super View ,这对您来说意味着另一个 super View :

iOS7:

UITableView *tableView = (UITableView *)cell.superview.superview;

iOS6"
UITableView *tableView = (UITableView *)cell.superview;

另一个变化你可以找到它 here :

似乎你的代码: UITableView table = (UITableView)[[[sender superview] superview] superview];返回 UITableViewCell不是 UITableView .

试试下面的:
UITableView *table = (UITableView*)[[[[[sender superview] superview] superview] superview] superview];

关于iOS7 中的 UITableViewCell indexPath 崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18919616/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com