clojure - 如何在 Clojure 中获取字符的 ascii 十进制值？

Question

user=> (char 65)
\A
user=> (char 97)
\a
user=> (str (char 65))
"A"
user=> (str (char 97))
"a"

这些是来自 ascii 十进制值的字符...
如何从字符中获取 ascii 十进制值？

Answer 1

user=> (doseq [c "aA"] (printf "%d%n" (int c)))
97
65
nil
user=> (map int "aA");;
(97 65)
user=> (apply str (map char [97 65]))
"aA"