c# - restsharp 发出多个异步请求

Question

使用 restsharp.org 请求 API 很容易，
但是当我需要调用两个不同的 API 时，第一个请求包含代码，在响应第二个开始后，我认为这是不正确的，
下面是我的代码:

var client = new RestClient("http://xxx.yyy.com/");

var requestHotels = new RestRequest("api/hotelUi/home/hotelList", Method.POST);
requestHotels.AddParameter("take", "16");                                               
IRestResponse hotels = client.Execute(requestHotels); 
List<Hotel> topHotels = JsonConvert.DeserializeObject<List<Hotel>>(hotels.Content); 

var requestCities = new RestRequest("api/hotelUi/home/cityList", Method.POST);
requestCities.AddParameter("take", "16");                                                 
IRestResponse cities = client.Execute(requestCities);
List<City> topCities = JsonConvert.DeserializeObject<List<City>>(cities.Content);    

正如你看到的城市请求等到酒店请求响应，但我认为它们都必须发送，并等到两个响应都回来。

我该怎么做？

Answer 1

注释是正确的，使用 ExecuteAsync(它也可以反序列化数据 - 请参阅 http://restsharp.org/ )与任务可能如下所示:

// Set up requests as before
var client = new RestClient("http://xxx.yyy.com/");

var requestHotels = new RestRequest("api/hotelUi/home/hotelList", Method.POST);
requestHotels.AddParameter("take", "16");  

var requestCities = new RestRequest("api/hotelUi/home/cityList", Method.POST);
requestCities.AddParameter("take", "16");     

var cancellationTokenSource = new CancellationTokenSource();

var hotelsTask = client.ExecuteTaskAsync<List<Hotel>>(requestHotels, cancellationTokenSource.Token);
var citiesTask = client.ExecuteTaskAsync<List<City>>(requestCities, cancellationTokenSource.Token);

var tasks = new List<Task> { hotelsTask, citiesTask };

// Pause execution here until both tasks are complete
await Task.WhenAll(tasks);

// Check status then use hotelsTask.Result and citiesTask.Result