lua - 即使值不正确，Roblox Lua if 语句仍在执行

Question

这是我游戏中的一个主要问题。我一直在尝试制作一个脚本来检测值何时为 1、2、3、4 或 5。但是，即使值为 0，if 语句仍将执行，使计时器在任何人进入之前启动电梯。这真的很烦人，我无法修复它。这是脚本:

local players = workspace.TestMode.Players
players.Value = 0
wait(5)
script.Parent.Text = "Waiting for players..."

function StartTimer()
  while true do
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      script.Parent.Text = "15"
      print("enough players")
      wait(0.1)
    else
      script.Parent.Text = "Waiting for players..."
      print("not enough players")
    end 
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "14"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "13"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "12"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "11"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "10"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "9"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "8"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "7"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "6"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "5"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "4"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "3"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "2"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "1"
    else
      script.Parent.Text = "Waiting for players..."
    end
    wait(0.1)
    if players.Value == 1 or 2 or 3 or 4 or 5 then
      wait(0.9)
      script.Parent.Text = "Teleporting players..."
    else
      script.Parent.Text = "Waiting for players..."
    end
  end
end
StartTimer()

Answer 1

在 Lua 中，除了 nil 和 false 之外的所有值都是 truthy 所以当在 bool 上下文中评估时，它们将被视为 是的。

if players.Value == 1 or 2 or 3 or 4 or 5 then

这意味着您的 if 条件是 players.Value == 1 true 或 2 true 并且很快。 2 始终为 true。所以你的 if 条件总是 true。

你的情况应该是这样的:

if players.Value == 1 or players.Value == 2 or players.Value == 3 or players.Value == 4 or players.Value == 5 then

---

或者你可以有一个更简单的条件，这里有一些想法:

if players.Value > 0 and players.Value <= 5 then

conditions = {[1] = true, [2] = true, [3] = true, [4] = true, [5] = true}

if conditions[players.Value] then