symfony2 类 "Doctrine\ORM\EntityRepository"的子类不是有效的实体或映射的父类(super class)

Question

namespace griffin\UserBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
/**
 * @ORM\Entity(repositoryClass="griffin\UserBundle\Entity\UserRepository")
 * @ORM\Table(name="users")
 */
class User {

    const STATUS_ACTIVE   = 1;
    const STATUS_INACTIVE = 0;

    /**
     * @ORM\Id
     * @ORM\Column(name="id_users", type="smallint")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $idUsers;

和 Repository 类

namespace griffin\UserBundle\Entity;
use Doctrine\ORM\EntityRepository;

class UserRepository extends EntityRepository {

    public function getAdmin()
    {
        return $this->getEntityManager()
                ->createQuery('select * from users where users_groups_id = 1')
                ->getResults;
    }
}

当我在 Controller 中调用它时

$results = $this->getDoctrine()
    ->getRepository('griffin\UserBundle\Entity\UserRepository')
    ->getAdmin();

var_dump($results);

我有错误 Class "griffin\UserBundle\Entity\UserRepository" sub class of "Doctrine\ORM\EntityRepository" is not a valid entity or mapped super class.

Answer 1

getRepository()将实体类作为第一个参数:

$results = $this->getDoctrine()
    ->getRepository('griffin\UserBundle\Entity\User')
    ->getAdmin();

注:快速浏览一下 EntityManager 总是一个好主意。类本身。如果这样做，您将看到 getRepository() 的此方法签名:

/**
 * Gets the repository for an entity class.
 *
 * @param string $entityName The name of the entity.
 *
 * @return EntityRepository The repository class.
 */
public function getRepository($entityName)
{
    //...
}