javascript - 矩阵游戏，条件是当用户选择 2 个相同颜色的球时，它应该破坏 2 个相同颜色的图案

Question

我正在尝试一个矩阵游戏，条件是:

• 当用户选择 2 个相同颜色的球时，这将破坏 2 个相同颜色的图案。

我已经正确完成了水平和垂直选择。但是当我尝试交叉选择(对 Angular 线)时它不起作用，我想，我在对 Angular 线选择条件下犯了一个错误。

这是我的代码，交叉选择没有匹配相同的颜色模式。这是我的对 Angular 线选择编码，下列条件是否正确？

    onCheckPattern: function(pPattern) {
    if (pPattern != null) {
        this.mPromptTimerTally = 0;
        this.mPromptMarkSpr.setPosition(-1000.0, -1000.0);

        if (this.mFirstCheckPattern === null) {
            this.mFirstCheckPattern = pPattern;
            this.mCheckMarkSpr.setPosition(this.mPatternsPos[this.mFirstCheckPattern.m_nRowIndex][this.mFirstCheckPattern.m_nColIndex]);
        } else {
            this.mSecondCheckPattern = pPattern;
            if (this.mSecondCheckPattern === this.mFirstCheckPattern) {
                //                    this.mSecondCheckPattern = null;
                //                    return;
            }

            var isAdjacent = false;

            //HORIZONTAL& VERTICAL
            if (this.mFirstCheckPattern.m_nRowIndex == this.mSecondCheckPattern.m_nRowIndex) {
                if (this.mFirstCheckPattern.m_nColIndex > 0 &&
                    this.mFirstCheckPattern.m_nColIndex - 1 == this.mSecondCheckPattern.m_nColIndex)
                    isAdjacent = true;

                else if (this.mFirstCheckPattern.m_nColIndex + 1 < this.m_nMatrixCol &&
                    this.mFirstCheckPattern.m_nColIndex + 1 == this.mSecondCheckPattern.m_nColIndex)
                    isAdjacent = true;
            } else if (this.mFirstCheckPattern.m_nColIndex == this.mSecondCheckPattern.m_nColIndex) {
                if (this.mFirstCheckPattern.m_nRowIndex > 0 &&
                    this.mFirstCheckPattern.m_nRowIndex - 1 == this.mSecondCheckPattern.m_nRowIndex)
                    isAdjacent = true;
                else if (this.mFirstCheckPattern.m_nRowIndex + 1 < this.m_nMatrixRow &&
                    this.mFirstCheckPattern.m_nRowIndex + 1 == this.mSecondCheckPattern.m_nRowIndex)
                    isAdjacent = true;

            }
            //       


            //DIAGONAL SELECTION
            else if (this.mFirstCheckPattern.m_nRowIndex + 1, this.mFirstCheckPattern.m_nColIndex - 1 && this.mSecondCheckPattern.m_nRowIndex, this.mSecondCheckPattern.m_nColIndex)

            {
                isAdjacent = true;
            } else if (this.mFirstCheckPattern.m_nRowIndex - 1 == this.mSecondCheckPattern.m_nRowIndex && this.mFirstCheckPattern.m_nColIndex - 1 == this.mSecondCheckPattern.m_nColIndex) {
                isAdjacent = true;
            }




            if (isAdjacent) {
                this.mCheckMarkSpr.setPosition(-1000.0, -1000.0);

                this.swapTwoPattern(this.mFirstCheckPattern, this.mSecondCheckPattern, false);
                this.mFirstCheckPattern = null;
                this.mSecondCheckPattern = null;
            } else {
                this.mCheckMarkSpr.setPosition(this.mPatternsPos[this.mSecondCheckPattern.m_nRowIndex][this.mSecondCheckPattern.m_nColIndex]);

                this.mFirstCheckPattern = this.mSecondCheckPattern;
                this.mSecondCheckPattern = null;
            }
        }
    }
},

Answer 1

线

            else if (this.mFirstCheckPattern.m_nRowIndex + 1, this.mFirstCheckPattern.m_nColIndex - 1 && this.mSecondCheckPattern.m_nRowIndex, this.mSecondCheckPattern.m_nColIndex)

我觉得很可疑。

稍微缩写一下，你正在写类似的东西

            else if (a + 1, b - 1 && c, d)

因为JavaScript comma operator的方式有效，这被解释为 else if (d)，因此 isAdjacent 将被设置为 true if d不为零。

尝试

            else if (this.mFirstCheckPattern.m_nRowIndex + 1 == this.mSecondCheckPattern.m_nRowIndex && this.mFirstCheckPattern.m_nColIndex - 1 == this.mSecondCheckPattern.m_nColIndex)

相反。