arrays - scala中的输入数组

Question

我是 scala 的新手，如何读取一行中给定的整数？例如:

5
10 20 30 40 50

我想将它存储在一个数组中。如何拆分输入并将其存储在数组中？

可以通过readInt() 方法读取单个整数，然后我使用readLine() 读取输入，但不知道如何拆分并将其存储在数组中.

Answer 1

没有评论:

scala> val in = "10 20 30 40 50"
in: String = 10 20 30 40 50

scala> (in split " ")
res0: Array[String] = Array(10, 20, 30, 40, 50)

scala> (in split " ") map (_.toInt)
res1: Array[Int] = Array(10, 20, 30, 40, 50)

有了注释，我很想要fscanf:

scala> val f"$i%d" = "10"
<console>:7: error: macro method f is not a case class, nor does it have an unapply/unapplySeq member
       val f"$i%d" = "10"
           ^

但我突然想到，对于您的用例，您需要一个简单的语法来扫描整数。

无需重复:

scala> val r = """(\d+)""".r
r: scala.util.matching.Regex = (\d+)

scala> r findAllMatchIn in
res2: Iterator[scala.util.matching.Regex.Match] = non-empty iterator

scala> .toList
res3: List[scala.util.matching.Regex.Match] = List(10, 20, 30, 40, 50)

https://issues.scala-lang.org/browse/SI-8268