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java - 以点文件的形式生成AST

转载 作者:行者123 更新时间:2023-12-04 01:59:26 25 4
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我正在使用 ANTLR4 生成 Java 源代码的 AST,我不得不转移到 ANTLR3,因为我没有得到太多帮助和文档,而且继续进行真的很难。我设法生成了 AST,但不是在可视化中格式。然后我遇到了一个很棒的 answer我确实能够在 DOT 文件中生成 AST,但有一个小问题。

我的代码:

import org.antlr.runtime.CommonTokenStream;
import org.antlr.runtime.ANTLRFileStream;
import org.antlr.runtime.tree.CommonTree;
import org.antlr.runtime.tree.DOTTreeGenerator;
import org.antlr.stringtemplate.StringTemplate;

class Main {

public static void main(String[] args) throws Exception {
parseFile("/home/satnam-sandhu/Workstation/ASTGenerator/resource/java/Blabla.java");
}

public static void parseFile(String f)throws Exception {

JavaLexer lexer = new JavaLexer(new ANTLRFileStream(f));
CommonTokenStream tokens = new CommonTokenStream(lexer);
JavaParser parser = new JavaParser(tokens);
CommonTree tree = (CommonTree)parser.compilationUnit().getTree();
DOTTreeGenerator gen = new DOTTreeGenerator();
StringTemplate st = gen.toDOT(tree);
System.out.println(st);

}

}

我正在使用 gradle,所以我通过以下方式构建项目:

gradle clean build

然后运行它并通过以下方式将输出通过管道传输到点文件:

java -jar ASTGenerator.jar > ast.dot

现在我面临的问题是,对于以下源代码:

class example{
public static void print(int a){
int b = a +1;
System.out.println(b);
}

public static void main(){
print(15);
}
}

我得到这个作为输出:

digraph {

ordering=out;
ranksep=.4;
bgcolor="lightgrey"; node [shape=box, fixedsize=false, fontsize=12, fontname="Helvetica-bold", fontcolor="blue"
width=.25, height=.25, color="black", fillcolor="white", style="filled, solid, bold"];
edge [arrowsize=.5, color="black", style="bold"]

n0 [label=""];
n1 [label="class"];
n2 [label="example"];
n3 [label="{"];
n4 [label="public"];
n5 [label="static"];
n6 [label="void"];
n7 [label="print"];
n8 [label="("];
n9 [label="int"];
n10 [label="a"];
n11 [label=")"];
n12 [label="{"];
n13 [label="int"];
n14 [label="b"];
n15 [label="="];
n16 [label="a"];
n17 [label="+"];
n18 [label="1"];
n19 [label=";"];
n20 [label="System"];
n21 [label="."];
n22 [label="out"];
n23 [label="."];
n24 [label="println"];
n25 [label="("];
n26 [label="b"];
n27 [label=")"];
n28 [label=";"];
n29 [label="}"];
n30 [label="public"];
n31 [label="static"];
n32 [label="void"];
n33 [label="main"];
n34 [label="("];
n35 [label=")"];
n36 [label="{"];
n37 [label="print"];
n38 [label="("];
n39 [label="15"];
n40 [label=")"];
n41 [label=";"];
n42 [label="}"];
n43 [label="}"];

n0 -> n1 // "" -> "class"
n0 -> n2 // "" -> "example"
n0 -> n3 // "" -> "{"
n0 -> n4 // "" -> "public"
n0 -> n5 // "" -> "static"
n0 -> n6 // "" -> "void"
n0 -> n7 // "" -> "print"
n0 -> n8 // "" -> "("
n0 -> n9 // "" -> "int"
n0 -> n10 // "" -> "a"
n0 -> n11 // "" -> ")"
n0 -> n12 // "" -> "{"
n0 -> n13 // "" -> "int"
n0 -> n14 // "" -> "b"
n0 -> n15 // "" -> "="
n0 -> n16 // "" -> "a"
n0 -> n17 // "" -> "+"
n0 -> n18 // "" -> "1"
n0 -> n19 // "" -> ";"
n0 -> n20 // "" -> "System"
n0 -> n21 // "" -> "."
n0 -> n22 // "" -> "out"
n0 -> n23 // "" -> "."
n0 -> n24 // "" -> "println"
n0 -> n25 // "" -> "("
n0 -> n26 // "" -> "b"
n0 -> n27 // "" -> ")"
n0 -> n28 // "" -> ";"
n0 -> n29 // "" -> "}"
n0 -> n30 // "" -> "public"
n0 -> n31 // "" -> "static"
n0 -> n32 // "" -> "void"
n0 -> n33 // "" -> "main"
n0 -> n34 // "" -> "("
n0 -> n35 // "" -> ")"
n0 -> n36 // "" -> "{"
n0 -> n37 // "" -> "print"
n0 -> n38 // "" -> "("
n0 -> n39 // "" -> "15"
n0 -> n40 // "" -> ")"
n0 -> n41 // "" -> ";"
n0 -> n42 // "" -> "}"
n0 -> n43 // "" -> "}"

}

使用 http://viz-js.com/ 时可视化输出是这样的: enter image description here

到目前为止我所有的作品都已上传here如果你们想深入了解我正在使用的语法文件。我认为语法文件中指定的选项也可能是原因。我是初学者,没有一点帮助就无法继续。提前致谢。 :)

最佳答案

我一直在寻找的答案得到了回答here通过 Bart Kiers但是对于想要在不修改语法的情况下生成 DOT 文件的人来说,可以通过此 repository 的帮助来打印预期的语法树。 .由于我没有在 ANTLR4 中找到很多关于点生成的文档,而且除了修改 ANTLR3 语法文件之外没有其他选择,我使用了 Federico Tomassetti示例并对其进行一些修改以生成我们自己的 DOT 文件。

您可以通过以下方式打印点文件输出:

import java.io.File;
import java.io.IOException;

import java.util.ArrayList;

import java.nio.charset.Charset;
import java.nio.file.Files;

import org.antlr.v4.runtime.ANTLRInputStream;
import org.antlr.v4.runtime.CommonTokenStream;
import org.antlr.v4.runtime.ParserRuleContext;
import org.antlr.v4.runtime.RuleContext;
import org.antlr.v4.runtime.tree.ParseTree;

public class ASTGenerator {

static ArrayList<String> LineNum = new ArrayList<String>();
static ArrayList<String> Type = new ArrayList<String>();
static ArrayList<String> Content = new ArrayList<String>();

private static String readFile() throws IOException {
File file = new File("resource/java/Blabla.java");
byte[] encoded = Files.readAllBytes(file.toPath());
return new String(encoded, Charset.forName("UTF-8"));
}

public static void main(String args[]) throws IOException{
String inputString = readFile();
ANTLRInputStream input = new ANTLRInputStream(inputString);
Java8Lexer lexer = new Java8Lexer(input);
CommonTokenStream tokens = new CommonTokenStream(lexer);
Java8Parser parser = new Java8Parser(tokens);
ParserRuleContext ctx = parser.compilationUnit();

generateAST(ctx, false, 0);

System.out.println("digraph G {");
printDOT();
System.out.println("}");

}

private static void generateAST(RuleContext ctx, boolean verbose, int indentation) {
boolean toBeIgnored = !verbose && ctx.getChildCount() == 1 && ctx.getChild(0) instanceof ParserRuleContext;

if (!toBeIgnored) {
String ruleName = Java8Parser.ruleNames[ctx.getRuleIndex()];
LineNum.add(Integer.toString(indentation));
Type.add(ruleName);
Content.add(ctx.getText());
}
for (int i = 0; i < ctx.getChildCount(); i++) {
ParseTree element = ctx.getChild(i);
if (element instanceof RuleContext) {
generateAST((RuleContext) element, verbose, indentation + (toBeIgnored ? 0 : 1));
}
}
}

private static void printDOT(){
printLabel();
int pos = 0;
for(int i=1; i<LineNum.size();i++){
pos=getPos(Integer.parseInt(LineNum.get(i))-1, i);
System.out.println((Integer.parseInt(LineNum.get(i))-1)+Integer.toString(pos)+"->"+LineNum.get(i)+i);
}
}

private static void printLabel(){
for(int i =0; i<LineNum.size(); i++){
System.out.println(LineNum.get(i)+i+"[label=\""+Type.get(i)+"\\n "+Content.get(i)+" \"]");
}
}

private static int getPos(int n, int limit){
int pos = 0;
for(int i=0; i<limit;i++){
if(Integer.parseInt(LineNum.get(i))==n){
pos = i;
}
}
return pos;
}
}

对于这样的源代码:

class example{
public static void main(){
int a;
a = 5;
}
}

输出将是:

digraph G {
00[label="compilationUnit\n classexample{publicstaticvoidmain(){inta;a=5;}}<EOF> "]
11[label="normalClassDeclaration\n classexample{publicstaticvoidmain(){inta;a=5;}} "]
22[label="classBody\n {publicstaticvoidmain(){inta;a=5;}} "]
33[label="methodDeclaration\n publicstaticvoidmain(){inta;a=5;} "]
44[label="methodModifier\n public "]
45[label="methodModifier\n static "]
46[label="methodHeader\n voidmain() "]
57[label="result\n void "]
58[label="methodDeclarator\n main() "]
49[label="block\n {inta;a=5;} "]
510[label="blockStatements\n inta;a=5; "]
611[label="localVariableDeclarationStatement\n inta; "]
712[label="localVariableDeclaration\n inta "]
813[label="integralType\n int "]
814[label="variableDeclaratorId\n a "]
615[label="expressionStatement\n a=5; "]
716[label="assignment\n a=5 "]
817[label="expressionName\n a "]
818[label="assignmentOperator\n = "]
819[label="literal\n 5 "]
00->11
11->22
22->33
33->44
33->45
33->46
46->57
46->58
33->49
49->510
510->611
611->712
712->813
712->814
510->615
615->716
716->817
716->818
716->819
}

将这段输出插入http://viz-js.com/你会得到这个作为输出:

您还可以通过以下方式将输出通过管道传输到 ast.dot 文件:

java -jar path-to-jar-file.jar > ast.dot

现在这不是完美的方法,但对我来说已经足够了。 :)

希望这对您有所帮助。

关于java - 以点文件的形式生成AST,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48435911/

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