c# - 自动夹具 + AutoMoq : Create mock with excluded property

Question

例如 ISomething是一个具有三个属性的接口(interface):string Name和 int Count和一些复杂的属性ImComplex (具有循环依赖等)我不想建立 AutoFixture。所以我需要 AutoFixture 来创建 ISomething 的 Mock与 Name和 Count由其默认算法和 ImComplex 设置为空。但是，如果我尝试像这样解决它，我会得到一个异常(exception):

fixture.Customize(new AutoConfiguredMoqCustomization());
var some = fixture.Build<ISomething>().Without(x=>x.ImComplex).Create<ISomething>();

Ploeh.AutoFixture.ObjectCreationException : The decorated ISpecimenBuilder could not create a specimen based on the request: RP.Core.IInformationUnit. This can happen if the request represents an interface or abstract class; if this is the case, register an ISpecimenBuilder that can create specimens based on the request. If this happens in a strongly typed Build expression, try supplying a factory using one of the IFactoryComposer methods.

我该怎么办？

Answer 1

Build禁用所有自定义(如方法文档中所述)，因此它不能与 AutoConfiguredMoqCustomization 一起使用.

如果问题是该属性具有循环依赖关系，那么您可以:

重新考虑你的设计(默认情况下，AutoFixture 在发现循环依赖时抛出它的原因，因为这些通常是设计气味)

配置 AutoFixture 以允许循环依赖，达到一定深度

fixture.Behaviors.OfType<ThrowingRecursionBehavior>().ToList()
    .ForEach(b => fixture.Behaviors.Remove(b));

int recursionDepth = 2;
fixture.Behaviors.Add(new OmitOnRecursionBehavior(recursionDepth));