javascript - 替换特定索引(数组)处的值

Question

大家晚上好

我有一个包含 24 个字符的数组

"hours": [
        "1",
        "1",
        "1",
        "1",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0",
        "0"
    ] 

我想搜索另一个索引数组；例如 [2, 5, 9, 10]

然后，转到第一个数组的(第一个数组的)位置(2、5、9和10)并将字符更改为该位置的“1”，并将数组的其余部分移动到“0"

有人可以指导我吗？

谢谢!

Answer 1

解决方案:

var hours = ["1", "1", "1", "1", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0"],
    positions = [2, 5, 9, 10];

for (var i = 0; i < hours.length; i++) {
  hours[i] = positions.includes(i) ? "1" : "0";   
}

console.log(hours);

// ["0", "0", "1", "0", "0", "1", "0", "0", "0", "1", "1", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0"]

演示: https://jsfiddle.net/gzynud0c/1/

---

As pointed out in the comments, the above solution works in all major browsers, including IE9+, without using a transpiler like Babel or using a polyfill.

以下适用于所有浏览器。

for (var i = 0; i < hours.length; i++) {
  hours[i] = ~positions.indexOf(i) ? "1" : "0";   
}

演示: https://jsfiddle.net/s59jt870/3/