typescript - 类验证器验证联合类型

Question

我有一个 mongoose discriminator schema ，这意味着数据将根据属性之一而不同。

class Feature {
  name: string
  option: ColorFeature|SizeFeature
}

class ColorFeature {
  kind: 'color'
  color: string
}

class SizeFeature {
  kind: 'size'
  size: number
}

验证 Feature 的正确方法是什么？类，以便它只接受 2 种不同的类型？

Answer 1

可以通过使用 validateNested() 来实现连同class-transformer discriminator

class BaseFeature {
  kind: 'size' | 'color'
}

class ColorFeature extends BaseFeature {
  kind: 'size'
  color: string
}

class SizeFeature extends BaseFeature {
  kind: 'size'
  size: number
}


class Feature {
  name: string

  @ValidateNested()
  @Type(() => BaseFeature, {
    keepDiscriminatorProperty: true,
    discriminator: {
      property: 'kind',
      subTypes: [
        { value: SizeFeature, name: 'size' },
        { value: ColorFeature, name: 'color' },
      ],
    },
  })
  option: SizeFeature | ColorFeature;
}