vim - 如何在 Vim 中删除指定符号后直到行尾的文本？

Question

我的数据格式如下:

id|name|things that I don't care

因此，对于每一行，我想在第二个 | 之后删除文本符号。
如何使用一个命令在 Vim 中执行此操作？
注:在第二个 | 之后实际上还有额外的管道, 自 |字符用作列的分隔符。

Answer 1

一种解决方案:

:%s!^\([^|]*|\)\{2\}\zs.*!!

说明:

% : 每一行

s : 字幕

! : 模式开始

^ : 行首

\( : 组开始

[^|]* : 任意数量的非管道字符

| : 后跟一个管道

\) : 群结束

\{2\} : 匹配该组的两个计数

\zs : 从这里开始模式匹配

.* : 任何字符

! : 模式结束和替换开始

! : 更换结束

这将使少于两个管道的行保持不变，并且还将处理多于两个管道的行......

之前

id name things that I don't care no pipes
id|name things that I don't care one pipe
id|name|things that I don't care two pipes
id|name|things that I don't care extra pipe at line end|
id|name|things that I don't care | extra pipe mid-line
id|name|things that I don't| care| two extra pipes
name|things that I don't care missing first column and pipe
|name|things that I don't care missing first column

后 :

id name things that I don't care no pipes
id|name things that I don't care one pipe
id|name| 
id|name| 
id|name| 
id|name| 
name|things that I don't care missing first column and pipe
|name|