perl - 遍历复杂的哈希结构

Question

我有以下散列结构 $chainStorage{$R1}{$S1}{$C1} =\@A1

$chainStorage = {
        'ACB' => {
               'E' => {'06' => [100, 200, 95]}
               'B' => {'23' => [20, 1000, 05, 30]}
        },
        'AFG' => {
               'C' => { '24' => [18, 23, 2300, 3456]}
        },
        'HJK' => {
               'A' => {'12' => [24, 25, 3200, 5668]}
               'D' => {'15' => [168]}
        }
}; 

比如ACB对应两个数组，[100, 200, 95]和[20, 1000, 05, 30]而 E 仅对应于 [100, 200, 95]。

现在，我需要将数组中与第一级键(例如 ACB)对应的所有元素加在一起。

也就是说，在另外一个hash结构中，我要ACB对应

100+200+95 + 20+1000+05+30 = 1450

如何通过$chainStorage实现这个功能？

Answer 1

你可以这样做:

#!/usr/bin/perl
use strict;
use warnings;
use Data::Dump qw(dump);

my $chainStorage = {
        'ACB' => {
               'E' => {'06' => [100, 200, 95]},
               'B' => {'23' => [20, 1000, 05, 30]}
        },
        'AFG' => {
               'C' => { '24' => [18, 23, 2300, 3456]}
        },
        'HJK' => {
               'A' => {'12' => [24, 25, 3200, 5668]},
               'D' => {'15' => [168]}
        }
}; 


while (my($k,$v) = each %$chainStorage) {
    my $sum = 0;
    while (my($k2,$v2) = each%$v) {
        while (my($k3,$v3) = each %$v2) {
            foreach (@$v3) {
                $sum += $_;
            }
        }
    }
    $chainStorage->{$k} = $sum;
}
dump$chainStorage;

输出:

{ ACB => 1450, AFG => 5797, HJK => 9085 }