python-3.x - 如何使用python3中的搜索从主字符串的空格前后获取子字符串？

Question

下面的例子，

import re

OUTPUT = '''
This is sample KLC-SOME345-Sample-VR demo test
'''

search = re.search('( .*Sample-VR)', OUTPUT, re.IGNORECASE)
if search != None:
    print(search.group(1))

结果如“KLC-SOME345-Sample-VR”

请帮助我如何获得准确的字符串。我也试过\s 和 ' ' 但没有用

Answer 1

import re

OUTPUT = '''This is sample KLC-SOME345-Sample-VR demo test'''

search = re.search(r'([^\s]*Sample-VR[^\s]*)', OUTPUT, re.IGNORECASE)
if search != None:
    print(search.group(1))

打印:

KLC-SOME345-Sample-VR