google-maps - 方向api : check if a place falls in the route path between 2 places

Question

我正在使用 Google Direction API 绘制 2 个地方 A 和 B 之间的路线路径。我能够做到这一点。现在，我需要检查给定的地点 C 是否落在 A 和 B 的路线路径中。

这是我从代码中生成的路由路径的快照。



下面是对应的代码:

function initialize() {
                var input = document.getElementById('searchTextFieldSource');
                var input1 = document.getElementById('searchTextFieldDestination');

                var autocomplete = new google.maps.places.Autocomplete(input);
                var autocomplete1 = new google.maps.places.Autocomplete(input1);
                google.maps.event.addListener(autocomplete1, 'place_changed', function () {
                    var place = autocomplete.getPlace();
                    document.getElementById('city1').value = place.name;
                    var place1Lat = place.geometry.location.lat();
                    var place1Lng = place.geometry.location.lng();
                    document.getElementById('cityLat1').value = place1Lat;
                    document.getElementById('cityLng1').value = place1Lng;

                    var obj = new Object();
                    obj.city =place.name;
                    obj.latitude = place.geometry.location.lat();
                    obj.longitude = place.geometry.location.lng();
                    locations.push(obj);


                    var place2 = autocomplete1.getPlace();
                    document.getElementById('city2').value = place2.name;
                    var place2Lat = place2.geometry.location.lat();
                    var place2Lng = place2.geometry.location.lng();
                    document.getElementById('cityLat2').value = place2Lat;
                    document.getElementById('cityLng2').value = place2Lng;

                    var obj = new Object();
                    obj.city = place2.name;
                    obj.latitude = place2.geometry.location.lat();
                    obj.longitude = place2.geometry.location.lng();
                    locations.push(obj);

                    directionsDisplay = new google.maps.DirectionsRenderer();
                    var startPlace = new google.maps.LatLng(place1Lat, place1Lng);

                    var mapOptions = {
                        zoom:7,
                        center: startPlace
                    }

                    var map = new google.maps.Map(document.getElementById('map'), mapOptions);
                    directionsDisplay.setMap(map);
                    //refreshMap(locations);

                    var start = $("#city1").val();
                    var end = $("#city2").val();
                    var request = {
                          origin:start,
                          destination:end,
                          travelMode: google.maps.TravelMode.DRIVING
                    };
                    directionsService.route(request, function(response, status) {
                        if (status == google.maps.DirectionsStatus.OK) {
                          directionsDisplay.setDirections(response);
                        }
                    });
                });
            }

我该怎么办？

Answer 1

您可以使用几何库(您可以通过将脚本 src 更改为 https://maps.googleapis.com/maps/api/js?sensor=false&libraries=geometry 来请求谷歌地图)并使用 isLocationOnEdge并使用 LatLng点 C 和从 DirectionsService 返回的折线.

https://developers.google.com/maps/documentation/javascript/geometry#isLocationOnEdge

话又说回来，C点可以总是 如果您将其添加为航路点，则在 A 和 B 之间的途中，因此确定 C 点是否“在路上”实际上是一个棘手的概念 - 离路多远以至于不能“在途中”？