python - 有没有更简单的方法来编写这个比较运算符语句？

Question

我是 Python 的新手。我有以下 if 语句:

if(userGuess == "0" or userGuess == "1" or userGuess == "2" or userGuess == "3" or userGuess == "4" or userGuess == "5" or userGuess == "6" or userGuess == "7" or userGuess == "8" or userGuess == "9"):
    print("\n>>>error: cannot use integers\n")
    continue

基本上，如果用户输入任何数字，循环将重置。有什么办法可以写出这个语句来让它更高效一点吗？ (即更少的代码和更清洁)

Answer 1

possibilities = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

if userGuess in possibilities:
    #do something

或者，如果您愿意与整数进行比较，您可以执行以下操作:

if userGuess < 10:
    #do something