lisp - GCL中的条件如何处理？

Question

handler-case 是处理 Common Lisp 条件的关键，但 Ubuntu 18.04 上的 GCL 2.6.12 认为它是一个未定义的函数:

>(handler-case (error "test") (error (condition) condition))                   
                                                                               
Error: UNDEFINED-FUNCTION :NAME HANDLER-CASE                                   
Fast links are on: do (si::use-fast-links nil) for debugging                   
Signalled by EVAL.                                                             
UNDEFINED-FUNCTION :NAME HANDLER-CASE                                          

Broken at EVAL.  Type :H for Help.                                             
    1  Return to top level.                                                    
>>

handler-bind 也是如此。 .
GCL 手册中唯一与处理条件或错误相关的功能是 GCL 特定的 universal-error-handler .
如何在 GCL 中处理条件，最好以其他 Lisp 支持的方式处理？

Answer 1

项目的 README.Debian 中说明了这种情况。 :

[...] The common lisp standard in effect when GCL was first released is known as "Common Lisp, the Language" (CLtL1) after a book by Steele of the same name providing this specification. Subsequently, a much expanded standard was adopted by the American National Standards Institute (ANSI), which is still considered the definitive common lisp language specification to this day.

[...]

To toggle the use of the ANSI image, set the environment variable GCL_ANSI to any non-empty string.

( This Debian bug 有更多信息。) handler-case需要 ANSI 支持，因此在基于 Debian 的系统上，GCL 需要以 GCL_ANSI 启动环境变量集；例如:

$ GCL_ANSI=1 gcl

为了反射(reflect)更改，启动消息的第一行从以下位置更改:

GCL (GNU Common Lisp)  2.6.12 CLtL1    Fri Apr 22 15:51:11 UTC 2016

至:

GCL (GNU Common Lisp)  2.6.12 ANSI    Fri Apr 22 15:51:11 UTC 2016