spring - 为复合 PK 生成的空 ID

Question

我有以下表格 以及以下关系表: , 它有一个复合 PK 如下:

用户角色.java

@RooJavaBean
@RooJpaEntity(identifierType = UserRolePK.class, versionField = "", table = "UserRole", schema = "dbo")
@RooDbManaged(automaticallyDelete = true)
@RooToString(excludeFields = { "idApplication", "idRole", "idUserName" })
public class UserRole {
}

UserRole_Roo_DbManaged.aj

@ManyToOne
@JoinColumn(name = "IdApplication", referencedColumnName = "IdApplication", nullable = false, insertable = false, updatable = false)
private Application UserRole.idApplication;

@ManyToOne
@JoinColumn(name = "IdRole", referencedColumnName = "IdRole", nullable = false, insertable = false, updatable = false)
private Role UserRole.idRole;

@ManyToOne
@JoinColumn(name = "IdUserName", referencedColumnName = "IdUserName", nullable = false, insertable = false, updatable = false)
private Users UserRole.idUserName;

但也存在一个PK表:

@RooIdentifier(dbManaged = true)
public final class UserRolePK {}

及其标识符类(UserRolePK_Roo_Identifier.aj)

privileged aspect UserRolePK_Roo_Identifier {

    declare @type: UserRolePK: @Embeddable;

    @Column(name = "IdRole", nullable = false)
    private Long UserRolePK.idRole;

    @Column(name = "IdUserName", nullable = false, length = 16)
    private String UserRolePK.idUserName;

    @Column(name = "IdApplication", nullable = false)
    private Long UserRolePK.idApplication;

我设置服务对象保存的方式是:

UserRole userRole= new UserRole();
userRole.setIdApplication(app);
userRole.setIdRole(invited);
userRole.setIdUserName(user);
appService.saveURole(userRole);

app之前已经设置并保存(同一交易)，以及invited和用户 对象。由于用户(来自具有复合 PK 的 Users 表:IdUserName，它是一个 String )定义如下，否则不起作用。

@RooJavaBean
@RooJpaEntity(versionField = "", table = "Users", schema = "dbo")
@RooDbManaged(automaticallyDelete = true)
@RooToString(excludeFields = { "quotations", "taxes", "userRoles", "idCompany", "idPreferredLanguage" })
public class Users {

    @Id
    //@GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "IdUserName", length = 16, insertable = true, updatable = true)
    private String idUserName;
}

所以，我得到的错误是:

org.springframework.orm.jpa.JpaSystemException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole; nested exception is javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole

Answer 1

试试这个:

public class UserRole {
   @PrePersist
   private void prePersiste() {
       if (getId() == null) {
           UserRolePK pk = new UserRolePK();
           pk.setIdApplication(getIdApplication());
           pk.setIdRole(getIdRole);
           pk.setIdUserName(getIdUserName());
           setId(pk);
       }
   }
}

Roo 正在生成 UserRole 实体及其 id 嵌入类的字段，但不是一回事(UserRole.idRole 与 UserRole.id 不同。身份角色)。在您的示例中，您填写了 UserRole 字段，但没有填写 id 字段。此代码会在实体持久化之前为您完成。

祝你好运!