python - Django-filter如何更改占位符以替换[无效名称]？

Question

我创建了一个过滤器来搜索多个字段(我必须只有一个搜索字段)，如下所示:

类 myFilter(django_filters.FilterSet):
full_search = django_filters.CharFilter(name='full_search', method='search_by_full_search')

def search_by_full_search(self, qs, name, value):
    for term in value.split():
        qs = qs.filter(Q(serial__icontains=term) | Q(id__icontains=term) | Q(name__icontains=term))
    return qs

class Meta:
    model = myModel
    fields = ['full_search', ]

但在 html 中，占位符显示了我的诡计!

<input type="text" name="full_search" class="form-control" placeholder="[invalid name]" title="" id="id_full_search">

是否可以通过其他方式进行更改？

Answer 1

我知道这已经被问过一段时间了，但刚刚解决了一个项目中的类似问题，所以在这里发布它以帮助其他人是否面临这个问题。

full_search = django_filters.CharFilter(method='search_by_full_search', label='Recherche') # change label field to reflect what the filter name should be

class Meta:
   model = myModel
   fields = ['full_search', ]

def search_by_full_search(self, qs, name, value):
    for term in value.split():
      qs = qs.filter(Q(serial__icontains=term) | Q(id__icontains=term) | 
      Q(name__icontains=term))
    return qs