gpt4 book ai didi

sql - 结合两个多个 bigquery SELECT FROM 语句

转载 作者:行者123 更新时间:2023-12-04 00:25:50 24 4
gpt4 key购买 nike

我对 BigQuery 和 SQL 比较陌生,所以我遇到的部分困难可能是我不知道如何描述我遇到的问题,以便能够搜索到答案,但我看过所以请温柔点。

我想做的是计算满足一组条件的唯一用户 ID 的总数,并将其除以唯一用户 ID 的总数。

例如统计所有购买过的唯一用户:

SELECT count(userId) 
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId)

并统计独立用户总数

 SELECT count(userId) 
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId)

我试着把查询写成

SELECT buyers/total 
FROM (SELECT COUNT(userId) AS buyers
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId),
COUNT(userId) as total
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId))

但它不起作用。我知道我做的事情从根本上是错误的,但我不确定它是什么。如果有任何帮助,我将不胜感激。

最佳答案

您可以像这样计算不同的用户:

SELECT
EXACT_COUNT_DISTINCT(userId) as buyers
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU"

连接它们的一种方法是添加一个静态标量值并将其用于连接:

SELECT
buyers/total
FROM (
SELECT
EXACT_COUNT_DISTINCT(userId) AS buyers,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU") a
JOIN (
SELECT
COUNT(userId) AS total,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute)) ) b
ON
a.scalar=b.scalar

关于sql - 结合两个多个 bigquery SELECT FROM 语句,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30651161/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com