search - grep 列出没有内容的文件名

Question

我们如何在使用 grep 搜索后只列出文件名？

当我使用

grep -i -R "search keyword" folder

它还会列出所有内联代码行。

Answer 1

来自 grep man 页面:

-L, --files-without-match Suppress normal output; instead print the name of each input file from which no output would normally have been printed. The scanning will stop on the first match.

-l, --files-with-matches Suppress normal output; instead print the name of each input file from which output would normally have been printed. The scanning will stop on the first match. (-l is specified by POSIX.)

对您来说，-l 选项会有所帮助。