angularjs - Angular 1.2 : Is it possible to exclude an input on form dirty checking?

Question

在下面的示例中，是否可以忽略下拉列表的脏状态？现在，如果用户更改所选人员，就会变得很脏。但我不在乎这个字段在我的表单验证中是否脏。

function TestingCtrl($scope) {
  $scope.company = '';
  $scope.persons = [{
    name: 'Alice'
  }, {
    name: 'Bob'
  }];


  $scope.selectedPerson = $scope.persons[0];

  $scope.checkForm = function() {
    if ($scope.personForm.$dirty) {
      alert('Form is dirty');
    } else {
      alert('Form is clean');
    }
  }

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.7/angular.min.js"></script>


<div ng-app>

  <div ng-controller="TestingCtrl">

    <form name="personForm" novalidate>
      Company:
      <input type="text" ng-model="company" required>
      <br>Persons:
      <select ng-options="p.name for p in persons" ng-model="selectedPerson"></select>

    </form>

    <br>
    <button ng-click="checkForm()">Check if dirty</button>

  </div>

</div>

Answer 1

boindiil 的基于指令的解决方案有效但有一个缺陷:如果表单的 $setPritine 会停止工作是手动执行的。这可以通过添加一个额外的行来解决输入的方法行为:

angular.module('myApp', []).directive('ignoreDirty', [function() {
    return {
    restrict: 'A',
    require: 'ngModel',
    link: function(scope, elm, attrs, ctrl) {
      ctrl.$setPristine = function() {};
      ctrl.$pristine = false;
    }
  }
}]);