selenium - headless 谷歌浏览器 : How to prevent sites to know whether their window is focused or not

Question

有没有办法阻止网站知道它们是否可见？

也许是命令行标志？我在这里查过，但找不到合适的https://peter.sh/experiments/chromium-command-line-switches/ .

我认为他们使用页面可见性 API:https://developer.mozilla.org/en-US/docs/Web/API/Page_Visibility_API

Answer 1

如果您的目标是欺骗可见性 API，则将这段脚本注入(inject)相关页面或框架中:

await page.evaluate(`
    Object.defineProperty(window.document,'hidden',{get:function(){return false;},configurable:true});
    Object.defineProperty(window.document,'visibilityState',{get:function(){return 'visible';},configurable:true});
    window.document.dispatchEvent(new Event('visibilitychange'));
`);

它首先覆盖 window.hidden让它返回 false .然后，它触发 visibilitychange在页面已经隐藏的情况下通知文档的事件。

或者在创建文档后立即覆盖 API:

await page.evaluateOnNewDocument(`
    Object.defineProperty(window.document,'hidden',{get:function(){return false;},configurable:true});
    Object.defineProperty(window.document,'visibilityState',{get:function(){return 'visible';},configurable:true});
`);