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python - 根据 Pandas DataFrame 中其他列的条件创建新列

转载 作者:行者123 更新时间:2023-12-04 00:02:01 25 4
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我有这个数据框:

+------+--------------+------------+
| ID | Education | Score |
+------+--------------+------------+
| 1 | High School | 7.884 |
| 2 | Bachelors | 6.952 |
| 3 | High School | 8.185 |
| 4 | High School | 6.556 |
| 5 | Bachelors | 6.347 |
| 6 | Master | 6.794 |
+------+--------------+------------+

我想创建一个对分数列进行分类的新列。我想给它贴上标签:“差”、“好”、“非常好”。

这可能看起来像这样:
+------+--------------+------------+------------+
| ID | Education | Score | Labels |
+------+--------------+------------+------------+
| 1 | High School | 7.884 | Good |
| 2 | Bachelors | 6.952 | Bad |
| 3 | High School | 8.185 | Very good |
| 4 | High School | 6.556 | Bad |
| 5 | Bachelors | 6.347 | Bad |
| 6 | Master | 6.794 | Bad |
+------+--------------+------------+------------+

我怎样才能做到这一点?

提前致谢

最佳答案

import pandas as pd 

# initialize list of lists
data = [[1,'High School',7.884], [2,'Bachelors',6.952], [3,'High School',8.185], [4,'High School',6.556],[5,'Bachelors',6.347],[6,'Master',6.794]]

# Create the pandas DataFrame
df = pd.DataFrame(data, columns = ['ID', 'Education', 'Score'])

df['Labels'] = ['Bad' if x<7.000 else 'Good' if 7.000<=x<8.000 else 'Very Good' for x in df['Score']]
df

ID Education Score Labels
0 1 High School 7.884 Good
1 2 Bachelors 6.952 Bad
2 3 High School 8.185 Very Good
3 4 High School 6.556 Bad
4 5 Bachelors 6.347 Bad
5 6 Master 6.794 Bad

关于python - 根据 Pandas DataFrame 中其他列的条件创建新列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59642338/

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