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assembly - 浮点程序给出无效结果

转载 作者:行者123 更新时间:2023-12-03 23:51:42 25 4
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我正在尝试在 x86 MASM 上运行这个浮点二次方程程序。这段代码可以在 Kip Irvine x86 教科书中找到,我想看看它在视觉上是如何工作的。以下代码如下:

include irvine32.inc 
.DATA
a REAL4 3.0
b REAL4 7.0
cc REAL4 2.0
posx REAL4 0.0
negx REAL4 0.0

.CODE


main proc
; Solve quadratic equation - no error checking
; The formula is: -b +/- squareroot(b2 - 4ac) / (2a)
fld1 ; Get constants 2 and 4
fadd st,st ; 2 at bottom
fld st ; Copy it
fmul a ; = 2a

fmul st(1),st ; = 4a
fxch ; Exchange
fmul cc ; = 4ac

fld b ; Load b
fmul st,st ; = b2
fsubr ; = b2 - 4ac
; Negative value here produces error
fsqrt ; = square root(b2 - 4ac)
fld b ; Load b
fchs ; Make it negative
fxch ; Exchange

fld st ; Copy square root
fadd st,st(2) ; Plus version = -b + root(b2 - 4ac)
fxch ; Exchange
fsubp st(2),st ; Minus version = -b - root(b2 - 4ac)

fdiv st,st(2) ; Divide plus version
fstp posx ; Store it
fdivr ; Divide minus version
fstp negx ; Store it

call writeint
exit
main endp
end main

所以我能够让我的程序完全编译、执行和工作。但是,每当我运行该程序时,都会得到以下结果:
+1694175115

为什么结果如此之大?我也尝试调用 writefloat 但它说这个过程不在 Irvine32.inc 或 Macros.inc 库中。有人可以告诉我为什么它不起作用以及需要修复什么吗?谢谢。

最佳答案

浮点数在特殊处理器 (FPU) 的特殊寄存器中处理并以特殊格式存储,不能被视为整数 (WriteInt)。浮点数包含有关数字的更多信息,如符号和指数。数字本身被更改为具有适当指数的 1 到 2 之间的数字,其中前导 1 通常被隐藏。在这里查看双格式:https://en.wikipedia.org/wiki/Double-precision_floating-point_format .这些数字不太可能准确。

至少从 11 年以来,Irvine32 库提供了函数 WriteFloat以指数形式显示 FPU 寄存器 ST0 的值。它不会弹出或释放该寄存器。

改变

call writeint


fld posx                ; Load floating point number into ST0
call WriteFloat ; Write ST0
ffree st[0] ; Free ST0 - don't forget it!
call Crlf ; New line
fld negx ; Load floating point number into ST0
call WriteFloat ; Write ST0
ffree st[0] ; Free ST0 - don't forget it!
call Crlf ; New line

如果您的图书馆没有 WriteFloat我建议从 Irvine 的主页下载并安装最新的文件: http://www.kipirvine.com/asm/examples/index.htm (第七版示例程序和链接库源代码)。您还可以使用另一个库,例如C 运行时库(msvcrt.inc 和 msvcrt.lib)或 Raymond Filiatreault's FPU library .

如果您不能使用提供浮点例程的库,则必须自己转换数字:
INCLUDE irvine32.inc

.DATA
a REAL4 3.0
b REAL4 7.0
cc REAL4 2.0
posx REAL4 0.0
negx REAL4 0.0

buf BYTE 1024 DUP (?)

.CODE

double2dec PROC C USES edi ; Args: ST(0): FPU-register to convert, EDI: pointer to string
LOCAL CONTROL_WORD:WORD, TEN:WORD, TEMP:WORD, DUMMY:QWORD

; modifying rounding mode
fstcw CONTROL_WORD
mov ax, CONTROL_WORD
or ah, 00001100b ; Set RC=11: truncating rounding mode
mov TEMP, ax
fldcw TEMP ; Load new rounding mode

; Check for negative
ftst ; ST0 negative?
fstsw ax
test ah, 001b
jz @F ; No: skip the next instructions
mov byte ptr [edi], '-' ; Negative sign
add edi, 1
@@:
FABS ; Abs (upper case to differ from C-library)

; Separate integer and fractional part & convert integer part into ASCII
fst st(1) ; Doubling ST(0) - ST(1)=ST(0)
frndint ; ST(0) to integer
fsub st(1), st(0) ; Integral part in ST(0), fractional part in ST(1)

; Move 10 to st(1)
mov TEN, 10
fild TEN
fxch

xor ecx, ecx ; Push/pop counter

@@: ; First loop
fst st(3) ; Preserve ST(0)
fprem ; ST(0) = remainder ST(0)/ST(1)
fistp word ptr TEMP ; ST(3) -> ST(2) !
push word ptr TEMP
inc ecx
fld st(2) ; Restore ST(0)
fdiv st(0), st(1)
frndint ; ST(0) to integer
fxam ; ST0 == 0.0?
fstsw ax
sahf
jnz @B ; No: loop

fxch st(2) ; ST(0) <-> ST(2) (fractional part)
ffree st(2)
ffree st(3)

@@: ; Second loop
pop ax
or al, '0'
mov [edi], al
inc edi
loop @B ; Loop ECX times

mov byte ptr [edi], '.' ; Decimal point
add edi, 1

; Isolate digits of fractional part and store ASCII
get_fractional:
fmul st(0), st(1) ; Multiply by 10 (shift one decimal digit into integer part)
fist word ptr TEMP ; Store digit
fisub word ptr TEMP ; Clear integer part
mov al, byte ptr TEMP ; Load digit
or al, 30h ; Convert digit to ASCII
mov byte ptr [edi], al ; Append it to string
add edi, 1 ; Increment pointer to string
fxam ; ST0 == 0.0?
fstsw ax
sahf
jnz get_fractional ; No: once more
mov byte ptr [edi], 0 ; Null-termination for ASCIIZ

; clean up FPU
ffree st(0) ; Empty ST(0)
ffree st(1) ; Empty ST(1)
fldcw CONTROL_WORD ; Restore old rounding mode

ret ; Return: EDI points to the null-terminated string
double2dec ENDP


main proc
; Solve quadratic equation - no error checking
; The formula is: -b +/- squareroot(b2 - 4ac) / (2a)
fld1 ; Get constants 2 and 4
fadd st,st ; 2 at bottom
fld st ; Copy it
fmul a ; = 2a

fmul st(1),st ; = 4a
fxch ; Exchange
fmul cc ; = 4ac

fld b ; Load b
fmul st,st ; = b2
fsubr ; = b2 - 4ac
; Negative value here produces error
fsqrt ; = square root(b2 - 4ac)
fld b ; Load b
fchs ; Make it negative
fxch ; Exchange

fld st ; Copy square root
fadd st,st(2) ; Plus version = -b + root(b2 - 4ac)
fxch ; Exchange
fsubp st(2),st ; Minus version = -b - root(b2 - 4ac)

fdiv st,st(2) ; Divide plus version
fstp posx ; Store it
fdivr ; Divide minus version
fstp negx ; Store it

; Write the results

fld posx ; Load floating point number into ST0
lea edi, buf ; EDI: pointer to a buffer for a string
call double2dec ; Convert ST0 to buf and pop
mov edx, edi ; EDX: pointer to a null-terminated string
call WriteString ; Irvine32

call Crlf ; Irvine32: New line

fld negx ; Load floating point number into ST0
lea edi, buf ; EDI: pointer to a buffer for a string
call double2dec ; Convert ST0 to buf and pop
mov edx, edi ; EDX: pointer to a null-terminated string
call WriteString ; Irvine32

call Crlf ; Irvine32: New line

exit ; Irvine32: ExitProcess
main ENDP
end main

关于assembly - 浮点程序给出无效结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44172017/

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