java - java中的代码执行顺序

Question

我正在运行以下代码

int x=4;
int y=3;
double z=1.5;
z=++x/y*(x-- +2);
int t=(++x/y);
    System.out.println(z); //7

想知道它是如何在什么时候产生 7 的

1. (x-- +2) =6

2. ++x/y=1.6666

   3=6*1.6666=10

Answer 1

z=++x/y*(x-- +2);

被评估为:

z = ++x / y * (x-- + 2);  // Substitute value of ++x, y and x--
  = 5 / 3 * (5 + 2);      // After this point, x will be 4. Evaluate parenthesized expr
  = 5 / 3 * 7   // Now, left-to-right evaluation follows
  = 1 * 7       // 5 / 3 due to integer division will give you 1, and not 1.66

和:

t = ++x / y;   // x is 4 here
  = 5 / 3
  = 1