python-3.x - 使用自定义正则表达式验证linkedIn url

Question

我正在尝试规范linkedin url。为此，我正在使用正则表达式 ^https:\/\/[w]{3}\.linkedin\.com\/.*$这需要根据新的要求进行更改。
唯一有效的模式是:

https://www.linkedin.com/in/XXXXXX-XXXXX-55301b41

https://www.linkedin.com/pub/XXXXXX-XXXXX-55301b41

https://www.linkedin.com/public-profile/in/XXXXXX-XXXX-b82a7b10a

https://www.linkedin.com/public-profile/pub/XXXXXX-XXXX-b82a7b10a

很少有坏的角落案例是:

https://www.linkedin.com/in/xxxx-xxxx-ab85a328/%7Bcountry%3Dde%2C+language%3Dde%7D?trk=people-guest_profile-result-card_result-card_full-click

https://www.linkedin.com/edu/school?id=18987

https://www.linkedin.com/in/xxxx-xxxx-55301b41/de

https://www.linkedin.com/pub/xxxxx-xxxxx/98/b7a/22b

https://it.linkedin.com/public-profile/in/xxxx-xxxxx-80520667?challengeId=AQEV3tHveORYsAAAAXQqx1N3bZ7fd44s5ngegJp6rC0UoWvhG2LtAhhgld8h3QyBxorfcLL2iuvK4xh_UKoGguxvX6sFx_nnZA&submissionId=7bc972ed-bfd1-2e16-c395-ad35cb550117

逻辑是:

必须以 https://www.linkedin.com/ 开头

必须有/in/、/pub/、/public-profile/in/、/public-profile/pub

应该以用户名结尾，即 XXXXXX-XXXXX-55301b41

Answer 1

仅使用您显示的示例，您能否尝试以下正则表达式。正则表达式的在线演示是:Online demo of regex

^http[s]?:\/\/www\.linkedin\.com\/(in|pub|public-profile\/in|public-profile\/pub)\/([\w]{6}-[\w]{1,}-[\w]+)$

说明:为上述添加详细说明。

^http[s]?:                    ##Checking if URL starts from http OR https.
\/\/www\.linkedin\.com\/      ##Then checking if domain is www.linkedin.com
(in|pub|public-profile\/in|public-profile\/pub)  ##Then checking if its followed by in OR pub OR public-profile/in OR public-profile/pub
\/([\w]{6}-[\w]{1,}-[\w]+)$   ##Checking if above is followed by / [\w] with 6 occurrences - [\w] with 1 or more occurrences and then [\w] with 1 or more occurrences.

注意:如果您想检查 url 应该只以 https 开头，然后更改 ^http[s]?至 ^https在上面的正则表达式中。
注2:以上将创建 2 个捕获组，如果您不想创建任何捕获组，请尝试以下操作。

^http[s]?:\/\/www\.linkedin\.com\/(?:in|pub|public-profile\/in|public-profile\/pub)\/(?:[\w]{6}-[\w]{1,}-[\w]+)$

Regex demo for note2 regex