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c - C中的红黑树实现

转载 作者:行者123 更新时间:2023-12-03 23:31:53 25 4
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我已经在 C 中实现了红黑树的插入部分。但是,当我调用 DISPLAY 函数时,我没有得到任何输出。我检查了 BST 实现(RBT 的某些部分)的功能正确性,它很好。任何帮助表示赞赏。
/* 根据 CSLR 实现红黑树 */

#include <stdio.h>
#include <stdlib.h>

struct rbtNode{
int key;
char color;
struct rbtNode *left;
struct rbtNode *right;
struct rbtNode *parent;
};

struct rbtNode* root = NULL;

void leftRotate(struct rbtNode *root,struct rbtNode *x){
struct rbtNode *y;
y = x->right; //Set y
x->right = y->left; // Turn y's left subtree into x's right subtree
if( y->left != NULL){
y->left->parent = x; //Bridge the y's left sublink
}
y->parent = x->parent; //Bridge x's old parent and y's parent
if( x->parent == NULL){
root = y;
}
else if( x->key == x->parent->left->key){
x->parent->left = y; //Bridge x's old parent's left or right child
}
else x->parent->right = y;
y->left = x; //put x on y's left
x->parent = y; //Take care of x's parent

return;
}

void rightRotate(struct rbtNode *root,struct rbtNode *y){
struct rbtNode *x;
x = y->left; //set x
y->left = x->right; //Turn x's right subtree into y's left subtree
if ( x->right != NULL){
x->right->parent = y;
}
x->parent = y->parent; //Bridge y's old parent and x's parent
if( y->parent == NULL){
root = x;
}
else if( y->key == y->parent->left->key){
y->parent->left = x; //Bridge y's old parent's left or right child
}
else y->parent->right = x;
x->right = y; //put y on x's right
y->parent = x; //Take care of y's parent

return;

}

void rbInsertFix(struct rbtNode *root,struct rbtNode *z){
struct rbtNode *y;
while (z->parent->color == 'r'){
if (z->parent->key == z->parent->parent->left->key){
y = z->parent->parent->right;
if (y->color == 'r'){
z->parent->color = 'b';
y->color = 'b';
z->parent->parent->color = 'r';
z = z->parent->parent;
}
else if (z->key == z->parent->right->key){
z = z->parent;
leftRotate(root,z);
}
z->parent->color = 'b';
z->parent->parent->color = 'r';
rightRotate(root,z->parent->parent);
}
else {
y = z->parent->parent->left;
if (y->color == 'r'){
z->parent->color = 'b';
y->color = 'b';
z->parent->parent->color = 'r';
z = z->parent->parent;
}
else if (z->key == z->parent->left->key){
z = z->parent;
rightRotate(root,z);
}
z->parent->color = 'b';
z->parent->parent->color = 'r';
leftRotate(root,z->parent->parent);
}
}
root->color = 'b';
}

void rbInsert(struct rbtNode *root, int val){
struct rbtNode *z = (struct rbtNode*)malloc(sizeof(struct rbtNode));
z->key = val;
z->left = NULL;
z->right = NULL;
z->color = 'r';
struct rbtNode *x = root;
struct rbtNode *y;
if ( root == NULL ){
root = z;
root->color = 'b';
return;
}
while ( x != NULL){
y = x;
if ( z->key < x->key){
x = x->left;
}
else x = x->right;
}
z->parent = y;
if ( y == NULL){
root = z;
}
else if( z->key < y->key ){
y->left = z;
}
else y->right = z;
rbInsertFix(root,z);

return;
}

/*Display RBT - Inorder Traversal*/
void inorderTree(struct rbtNode* root){
struct rbtNode* temp = root;
if (temp != NULL){
inorderTree(temp->left);
printf(" %d-%c ",temp->key,temp->color);
inorderTree(temp->right);
}
return;
}

int main(int argc, char* argv[]){
int loop = 1;
while(loop){
printf("\nRed Black Tree Management - Enter your choice : ");
printf("\n1\tInsert into RBT\n2\tDisplay RBT inorder\n");
int choice;
int val;
scanf("%d",&choice);
switch(choice){
case 1:
printf("\nEnter the integer you want to add : ");
scanf("%d",&val);
rbInsert(root,val);
break;

case 2:
printf("\nInorder tree traversal left-root-right\n");
inorderTree(root);
break;

default:
printf("\nInvalid Choice\n");
}
printf("\nPress '0' to terminate and '1' to continue : ");
scanf("%d",&loop);
}

return 0;
}

最佳答案

void rbInsert(struct rbtNode *root, int val)你路过root作为指针值。在 C 中,您不能通过按值传递来更新指针。
改变

void rbInsert(struct rbtNode *root, int val)


void rbInsert(int val)

它将正常工作,因为它将使用全局 root .

关于c - C中的红黑树实现,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14253816/

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