SQL Sum 当天的多个值

Question

这是我的 table

TIME                     Status
2012-11-15 8:30:00.000   "WAS_FLOW"
2012-11-15 9:00:00.000   "WAS_FLOW"
2012-11-15 10:30:00.000  "H2_FLOW"
2012-11-11 12:14:00.00   "O23HZ_FLOW"
2012-11-11 8:00.00.000   "AZ_FLOW"
2012-11-12 9:00.000      "BZ_FLOW"

我希望我的结果显示:

TIME         "WAS FLOW"    
2012-11-11   0
2012-11-12   0
2012-11-15   2

Answer 1

这里的其他答案都有轻微的故障。我希望这是一个开箱即用为您服务的工具。

SELECT
  DATEADD(DAY, DATEDIFF(DAY, 0, [time]), 0)             AS [date],
  SUM(CASE WHEN status = 'WAS_FLOW' THEN 1 ELSE 0 END)  AS [count]
FROM
  yourTable
GROUP BY
  DATEADD(DAY, DATEDIFF(DAY, 0, [time]), 0)