ecmascript-6 - 使用 map 和箭头功能将 2 个列表合二为一

Question

我有 2 个列表，我想将它们组合起来，以便我可以将它们填充到一个列表中。我知道这可以使用嵌套的 for 循环来完成，但是，由于我必须循环的数据量，我试图避免 for 循环。我想使用箭头函数或其他任何东西来实现这一点。

列表一:

let fields = [
    {
        field: "Name",
        fieldType: "Text"
    },
    {
        field: "Active__c",
        fieldType: "Boolean"
    },
    {
        field: "Contact",
        fieldType: "Relationship"
    }
];

列表二:

let rows = [
    {
        contact: {
            Name: "Joe",
            Active__c: true,
            Contact: "SomeContact"
        }
    },
    {
        contact: {
            Name: "Rachel",
            Active__c: true
        }
    },
    {
        contact: {
            Name: "Ross",
            Active__c: true
        }
    },
    {
        contact: {
            Name: "Monica",
            Active__c: true
        }
    }
];

当前代码:

let output = rows.map(row => ({
    id: row.Id,
    data: {
        value: fields.map(field => (row.contact[field.field])),
        field: fields.map(field => field.field)
    }
}));

此代码的输出:

[
    {
        "data": {
            "value": [
                "Joe",
                true,
                "SomeContact"
            ],
            "field": [
                "Name",
                "Active__c",
                "Contact"
            ]
        }
    },
    {
        "data": {
            "value": [
                "Rachel",
                true,
                null
            ],
            "field": [
                "Name",
                "Active__c",
                "Contact"
            ]
        }
    },
    {
        "data": {
            "value": [
                "Ross",
                true,
                null
            ],
            "field": [
                "Name",
                "Active__c",
                "Contact"
            ]
        }
    },
    {
        "data": {
            "value": [
                "Monica",
                true,
                null
            ],
            "field": [
                "Name",
                "Active__c",
                "Contact"
            ]
        }
    }
]

所需输出:

[
    data : [
        [
            {
                field : "Name",
                type: "Text",
                value : "Joe"
            },
            {
                field : "Active__c",
                type: "Boolean",
                value : true
            },
            {
                field : "Contact",
                type: "Relationship",
                value : "SomeContact"
            }
        ],
        [
            {
                field : "Name",
                type: "Text",
                value : "Rachel"
            },
            {
                field : "Active__c",
                type: "Boolean",
                value : false
            },
            {
                field : "Contact",
                type: "Relationship",
                value : "SomeContact Two"
            }
        ],
        [
            ...
        ],
        [
            ...
        ]
    ]
]

我怎样才能做到这一点？

Answer 1

data属性是唯一的，必须在创建对象时内联定义(而不是您在所需输出中拥有的数组)。你要 map fields数组到 rows 的每个元素然后填写每个field数据与 row数据(如果存在)。另外，我看不到 Id内的任何行对象上的字段 rows大批。此代码集 null如果 field不存在:

let output = {
  data: rows.map(({ contact }) => 
    fields.map(({ field, fieldType: type }) => ({
      field,
      type,
      value: field in contact ? contact[field] : null // Set null if contact has no field
    }))
  )
}

运行此代码片段以查看结果:

let fields = [
  {
    field: "Name",
    fieldType: "Text"
  },
  {
    field: "Active__c",
    fieldType: "Boolean"
  },
  {
    field: "Contact",
    fieldType: "Relationship"
  }
];

let rows = [
  {
    contact: {
      Name: "Joe",
      Active__c: true,
      Contact: "SomeContact"
    }
  },
  {
    contact: {
      Name: "Rachel",
      Active__c: true
    }
  },
  {
    contact: {
      Name: "Ross",
      Active__c: true
    }
  },
  {
    contact: {
      Name: "Monica",
      Active__c: true
    }
  }
];

let output = {
  data: rows.map(({ contact }) => 
    fields.map(({ field, fieldType: type }) => ({
      field,
      type,
      value: field in contact ? contact[field] : null
    }))
  )
}

document.getElementById('output').appendChild(
  document.createTextNode(JSON.stringify(output, null, 2))
);

<pre id="output"></pre>