c# - 将平面字典序列化为多子对象 JSON

Question

在 C# 中，我有一个扁平的 Dictionary<string, string>，其中键是 obj1/obj2/obj3 的形式，值是直接字符串。现在我想将其序列化为子对象，因此示例值:

var dict = new Dictionary<string, string> { {"foo/bar/baz1", "123" }, {"foo/baz", "456" }, { "foo/abc", "def" } };

应该导致:

{
     "foo": {
         "bar": {
             "baz1": "123"
         },
         "baz": "456",
         "abc": "def"
     }
}

(可选)我想删除输出中“123”和“456”周围的引号，如果它们可以解释为数字或 bool 值。

我正在使用 Newtonsoft.JSON

Answer 1

您可以使用 JObject 方法将源字典解析为 JObject.FromObject 。然后遍历所有属性，使用 string.Split 拆分它们并递归解析为新的 JObject ，表示属性树。最后使用 JObject.Add 将此对象添加到目标对象，或者如果给定的键已存在则更新它

var dict = new Dictionary<string, string> { { "foo/bar/baz1", "123" }, { "foo/baz", "456" }, { "foo/abc", "def" } };
var source = JObject.FromObject(dict);
var dest = new JObject();

foreach (var property in source.Properties())
{
    //split the name into parts
    var items = property.Name.Split(new[] { "/" }, StringSplitOptions.RemoveEmptyEntries);
    var item = items.FirstOrDefault();
    if (string.IsNullOrEmpty(item))
        continue;

    //get JObject representing a properties tree
    var result = WriteItems(items.Skip(1).ToList(), property.Value);

    //check that destination already contains top property name (e.g. 'foo')
    if (dest.ContainsKey(item))
    {
        (dest[item] as JObject)?.Add(result.First);
    }
    else
    {
        dest.Add(item, result);
    }
}

Console.WriteLine(dest.ToString());

//local function to recursively go through all properties and create a result JObject
JObject WriteItems(IList<string> items, JToken value)
{
    var item = items.FirstOrDefault();
    items.RemoveAt(0);

    if (!items.Any()) //no more items in keys, add the value
        return new JObject(new JProperty(item, value));

    return new JObject(new JProperty(item, WriteItems(items, value)));
}

它产生以下输出

{
  "foo": {
    "bar": {
      "baz1": "123"
    },
    "baz": "456",
    "abc": "def"
  }
}

此外，上面的代码允许您处理具有任何深度的属性树。我不认为有一种内置的方法可以将 foo/bar/baz1 之类的结构序列化为 Json.NET 中的子对象