android - 没有通过 REST 调用接收 json 数据

Question

我正在尝试使用改造来使用我自己的 REST 调用。我关于它为什么不起作用的唯一线索是它说信息的类型是“text/html”，即使我确定它是 json。话虽如此，我还没有找到任何解决我问题的答案。

有效载荷:

  [
    {
        "user_id": "32",
        "username": "Marko",
        "last_activity": "2020-04-26 20:44:00",
        "user_image": "slika2"
    },
    {
        "user_id": "33",
        "username": "dejan",
        "last_activity": "2020-04-26 20:44:00",
        "user_image": "slika3"
    }
]

我的聊天课:

public class Chat {

    @SerializedName("user_id")
    private String userId;

    private String username;

    @SerializedName("last_activity")
    private String lastActivity;

    @SerializedName("user_image")
    private String userImage;\

    ...constructor/getters

   }

API接口(interface):

@FormUrlEncoded
@POST("api_get_all_chats.php")
Call<List<Chat>> getChats(
        @Field("id") String id
);

API客户端:

public static Retrofit getClient() {

        HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
        interceptor.level(HttpLoggingInterceptor.Level.BODY);
        OkHttpClient client = new OkHttpClient.Builder().addInterceptor(interceptor).build();
        retrofit = new Retrofit.Builder()
                .baseUrl("http://MYIP/emob%20projekat/api/")
                .addConverterFactory(GsonConverterFactory.create())
                .client(client)
                .build();
        return retrofit;
    }

整个请求:

        apiInterface = ApiClient.getClient().create(userApi.class);

        Call<List<Chat>> call = apiInterface.getChats(u.getUserInfo().getUserId());

        call.enqueue(new Callback<List<Chat>>() {
            @Override
            public void onResponse(Call<List<Chat>> call, Response<List<Chat>> response) {
                chatList = new ArrayList<>(response.body());
                chatAdapter = new ChatAdapter(getApplication().getApplicationContext(), R.layout.user_view, chatList);
                listView.setAdapter(chatAdapter);
            }

            @Override
            public void onFailure(Call<List<Chat>> call, Throwable t) {
                Toast.makeText(getApplication().getApplicationContext(), "ne valja" , Toast.LENGTH_LONG).show();

            }
        });

任何我搞砸的线索都将不胜感激。

Answer 1

当我解码时你的基本网址有空间我得到了

http://MYIP/emob projekat/api/

我建议您放置不编码的基本 URL