gpt4 book ai didi

c# - 如何通过在 C# 中生成 IL 将 Action 转换为编译表达式或 DynamicMethod?

转载 作者:行者123 更新时间:2023-12-03 23:01:30 26 4
gpt4 key购买 nike

我必须处理维护一个库,该库允许用户针对它注册一个通用处理程序(Action<T>),然后一旦它收到一个事件,它就会通过每个注册的处理程序并将事件传递给它们。为了使问题简短,让我们跳过这样做的原因。
由于这种设计,我们不得不调用 DynamicInvoke通过每个事件时;这被证明是相当缓慢的,因此需要使用 IL 生成将委托(delegate)转换为 CompiledExpression 或 DynamicMethod。我已经看到了为 PropertyGetters ( Matt Warren's excellent article ) 实现此功能的各种示例,但我无法让它与 Action<T> 一起使用在哪里 T可以是 ValueType 或 ReferenceType。
这是一个当前(缓慢)的工作示例(为简洁起见):

void Main()
{
var producer = new FancyEventProduder();
var fancy = new FancyHandler(producer);

fancy.Register<Base>(x => Console.WriteLine(x));
producer.Publish(new Child());
}

public sealed class FancyHandler
{
private readonly List<Delegate> _handlers;

public FancyHandler(FancyEventProduder produer)
{
_handlers = new List<Delegate>();
produer.OnMessge += OnMessage;
}

public void Register<T>(Action<T> handler) => _handlers.Add(handler);

private void OnMessage(object sender, object payload)
{
Type payloadType = payload.GetType();
foreach (Delegate handler in _handlers)
{
// this could be cached at the time of registration but has negligable impact
Type delegParamType = handler.Method.GetParameters()[0].ParameterType;
if(delegParamType.IsAssignableFrom(payloadType))
{
handler.DynamicInvoke(payload);
}
}
}
}

public sealed class FancyEventProduder
{
public event EventHandler<object> OnMessge;

public void Publish(object payload) => OnMessge?.Invoke(this, payload);
}

public class Base { }
public sealed class Child : Base { }

最佳答案

不确定这是否是个好主意:

public sealed class FancyHandler
{
private readonly List<Tuple<Delegate, Type, Action<object>>> _handlers = new List<Tuple<Delegate, Type, Action<object>>>();

public FancyHandler(FancyEventProduder produer)
{
produer.OnMessge += OnMessage;
}

public void Register<T>(Action<T> handler)
{
_handlers.Add(Tuple.Create((Delegate)handler, typeof(T), BuildExpression(handler)));
}

private static Action<object> BuildExpression<T>(Action<T> handler)
{
var par = Expression.Parameter(typeof(object));
var casted = Expression.Convert(par, typeof(T));
var call = Expression.Call(Expression.Constant(handler.Target), handler.Method, casted);
var exp = Expression.Lambda<Action<object>>(call, par);
return exp.Compile();
}

private void OnMessage(object sender, object payload)
{
Type payloadType = payload.GetType();

foreach (var handlerDelegate in _handlers)
{
// this could be cached at the time of registration but has negligable impact
Type delegParamType = handlerDelegate.Item2;

if (delegParamType.IsAssignableFrom(payloadType))
{
handlerDelegate.Item3(payload);
}
}
}
}
请注意,即使不使用表达式树,也可以重用一些较小的想法:保存 typeof(T)而不是多次调用 handler.Method.GetParameters()[0].ParameterType例如。
一些测试用例:
fancy.Register<Base>(x => Console.WriteLine($"Base: {x}"));
fancy.Register<Child>(x => Console.WriteLine($"Child: {x}"));
fancy.Register<object>(x => Console.WriteLine($"object: {x}"));
fancy.Register<long>(x => Console.WriteLine($"long: {x}"));
fancy.Register<long?>(x => Console.WriteLine($"long?: {x}"));
fancy.Register<int>(x => Console.WriteLine($"int: {x}"));
fancy.Register<int?>(x => Console.WriteLine($"int?: {x}"));

producer.Publish(new Base());
producer.Publish(new Child());
producer.Publish(5);
完整的表达式树(类型检查移到表达式树的内部,其中 as 完成而不是 IsAssignableFrom )
public sealed class FancyHandler
{
private readonly List<Action<object>> _handlers = new List<Action<object>>();

public FancyHandler(FancyEventProduder produer)
{
produer.OnMessge += OnMessage;
}

public void Register<T>(Action<T> handler)
{
_handlers.Add(BuildExpression(handler));
}

private static Action<object> BuildExpression<T>(Action<T> handler)
{
if (typeof(T) == typeof(object))
{
return (Action<object>)(Delegate)handler;
}

var par = Expression.Parameter(typeof(object));

Expression body;

if (typeof(T).IsValueType)
{
// We remove the nullable part of value types
Type type = Nullable.GetUnderlyingType(typeof(T)) ?? typeof(T);

var unbox = Expression.Unbox(par, typeof(T));
body = Expression.IfThen(Expression.TypeEqual(par, type), Expression.Call(Expression.Constant(handler.Target), handler.Method, unbox));

if (type != typeof(T))
{
// Nullable type
// null with methods that accept nullable type: call the method
body = Expression.IfThenElse(Expression.Equal(par, Expression.Constant(null)), Expression.Call(Expression.Constant(handler.Target), handler.Method, Expression.Constant(null, typeof(T))), body);
}
}
else
{
// Imagine the resulting code will be:

// (object par) =>
// {
// if (par == null)
// {
// handler(null);
// }
// else
// {
// T local;
// local = par as T;
// if (local != null)
// {
// handler(local);
// }
// }
// }

var local = Expression.Variable(typeof(T));

var typeAs = Expression.Assign(local, Expression.TypeAs(par, typeof(T)));

var block = Expression.Block(new[]
{
local,
},
new Expression[]
{
typeAs,
Expression.IfThen(Expression.NotEqual(typeAs, Expression.Constant(null)), Expression.Call(Expression.Constant(handler.Target), handler.Method, typeAs))
});

// Handling case par == null, call the method
body = Expression.IfThenElse(Expression.Equal(par, Expression.Constant(null)), Expression.Call(Expression.Constant(handler.Target), handler.Method, Expression.Constant(null, typeof(T))), block);
}

var exp = Expression.Lambda<Action<object>>(body, par);
return exp.Compile();
}

private void OnMessage(object sender, object payload)
{
foreach (var handlerDelegate in _handlers)
{
handlerDelegate(payload);
}
}
}
这个版本甚至支持 null :
producer.Publish(null);
第三个版本,基于@BorisB 的想法,这个版本避免使用 Expression。并直接使用委托(delegate)。它应该有更短的预热时间(没有要编译的 Expression 树)。仍然有一个小的反射问题,但幸运的是这个问题只在添加新的处理程序时出现(有注释解释它)。
public sealed class FancyHandler
{
private readonly List<Action<object>> _handlers = new List<Action<object>>();

public FancyHandler(FancyEventProduder produer)
{
produer.OnMessge += OnMessage;
}

public void Register<T>(Action<T> handler)
{
if (typeof(T).IsValueType)
{
_handlers.Add(BuildExpressionValueType(handler));
}
else
{
// Have to use reflection here because the as operator requires a T is class
// this check is bypassed by using reflection
_handlers.Add((Action<object>)_buildExpressionReferenceTypeT.MakeGenericMethod(typeof(T)).Invoke(null, new[] { handler }));
}
}

private static Action<object> BuildExpressionValueType<T>(Action<T> handler)
{
// We remove the nullable part of value types
Type type = Nullable.GetUnderlyingType(typeof(T)) ?? typeof(T);

if (type == typeof(T))
{
// Non nullable
return (object par) =>
{
if (par is T)
{
handler((T)par);
}
};
}

// Nullable type
return (object par) =>
{
if (par == null || par is T)
{
handler((T)par);
}
};
}

private static readonly MethodInfo _buildExpressionReferenceTypeT = typeof(FancyHandler).GetMethod(nameof(BuildExpressionReferenceType), BindingFlags.Static | BindingFlags.NonPublic);

private static Action<object> BuildExpressionReferenceType<T>(Action<T> handler) where T : class
{
if (typeof(T) == typeof(object))
{
return (Action<object>)(Delegate)handler;
}

return (object par) =>
{
if (par == null)
{
handler((T)par);
}
else
{
T local = par as T;

if (local != null)
{
handler(local);
}
}
};
}

private void OnMessage(object sender, object payload)
{
foreach (var handlerDelegate in _handlers)
{
handlerDelegate(payload);
}
}
}

关于c# - 如何通过在 C# 中生成 IL 将 Action<T> 转换为编译表达式或 DynamicMethod?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65438939/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com