java - 如何处理具有相同 catch block 的解析数字？

Question

我经常遇到需要解析数值(例如使用 Integer.parseInt 或 Double.parseDouble)并且我有多个值的情况。问题是我发现自己不得不重复异常处理，它变得很难看。例如，采用以下代码:

double lowVal, mediumVal, highVal;
String lowString = "1.2", mediumString = "null", highString = "7.9";

try {
    lowVal = parseDouble(lowString);
} catch (NumberFormatException NaN) {
    //Don't care, just carry on trying to parse the rest...
}

try {
    mediumVal = parseDouble(mediumString);
} catch (NumberFormatException NaN) {
    //Don't care, just carry on trying to parse the rest...
}

try {
    highVal = parseDouble(highString);
} catch (NumberFormatException NaN) {
    //Don't care, just carry on trying to parse the rest...
}

是否有处理这种情况的良好模式？

我不想使用单次 try catch ，因为我想继续解析其余数字。

我应该提一下，在这个例子中，值没有被初始化，但在实际的程序代码中它们会被初始化。仅当字符串值可解析时才应进行赋值。

Answer 1

只是提取一个方法:

double lowVal, mediumVal, highVal;
String lowString = "1.2", mediumString = "null", highString = "7.9";

lowVal = parseDouble(lowString);
mediumVal = parseDouble(mediumString);
highVal = parseDouble(highString);

double parseDouble(String s) {
    try {
        return Double.parseDouble(s);
    } catch (NumberFormatException e) {
        return Double.NAN;
    } 
}

或

Double lowVal;
Double mediumVal;
Double highVal;
String lowString = "1.2", mediumString = "null", highString = "7.9";

lowVal = parseDouble(lowString);
mediumVal = parseDouble(mediumString);
highVal = parseDouble(highString);

Double parseDouble(String s) {
    try {
        return Double.parseDouble(s);
    } catch (NumberFormatException e) {
        return null;
    } 
}