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android - 如何在 Android 中实现 Telenor easypay API

转载 作者:行者123 更新时间:2023-12-03 22:55:53 27 4
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我正在实现 Telenor easypay API,其中包含两个 Web 服务到第一个我发布我的商店 ID 和其他信息,这些信息让我成功响应 Auth_token 和 postbackurl。当我将身份验证 token 和回发 URL 发布到下一个 Web 服务 URL https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf 时将我重定向到 easypaisa 结帐屏幕,该屏幕在 easypay 结帐屏幕上显示以下错误。
please click below link to see error screenshot
我的代码:

private class PostTask extends AsyncTask < String, String, String > {
@Override
protected void onPreExecute() {
super.onPreExecute();
mBT.setEnabled(false);
}

@Override
protected String doInBackground(String...data) {

OkHttpClient client; // = new OkHttpClient();
client = getUnsafeOkHttpClient();
client.setHostnameVerifier(new HostnameVerifier() {
@Override
public boolean verify(String hostname, SSLSession session) {
return true;
}
});

MediaType mediaType = MediaType.parse("application/x-www-form-urlencoded");
RequestBody body = RequestBody.create(mediaType, "amount=10&orderRefNum=110&storeId=xxxx&postBackURL=https://www.jeevaysehat.com/");
Request request = new Request.Builder()
.url("https://easypaystg.easypaisa.com.pk/easypay/Index.jsf")
.post(body)
.addHeader("content-type", "application/x-www-form-urlencoded")
.addHeader("cache-control", "no-cache")
.build();
Response response = null;
String resp = null;
try {
response = client.newCall(request).execute();
resp = response.body().string();
} catch (IOException e) {
e.printStackTrace();
}

//return resp;
return response.request().url().toString();
}

@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
Log.e("data", s);
try {
mBT.setEnabled(true);
String[] ist = s.split("=");
String[] snd = ist[1].split("&");
Token = snd[0];

Log.e("token", Token);
Log.e("posturl", ist[2]);

pburl = ist[2];
medPost.setText(pburl);
medtoken.setText(Token);


// Log.e("pburl", pburl);
/* Intent ii = new Intent(MainActivity.this, Payment_details.class);
ii.putExtra("data", token);
startActivity(ii);*/
//http://jeevaysehat.com/?auth_token=260915100358342650147434472217522869797&postBackURL=http%3A%2F%2Fjeevaysehat.com%2F


} catch (Exception e) {

}
}
}

private class PostTask1 extends AsyncTask < String, String, String > {
String mtoken;
String PBURL;

public PostTask1(String token, String pb) {
mtoken = token;
PBURL = pb;
}

@Override
protected String doInBackground(String...data) {


OkHttpClient client; // = new OkHttpClient();
client = getUnsafeOkHttpClient();
client.setHostnameVerifier(new HostnameVerifier() {
@Override
public boolean verify(String hostname, SSLSession session) {
return true;
}
});
MediaType mediaType = MediaType.parse("application/x-www-form-urlencoded");
RequestBody body = RequestBody.create(mediaType, "auth_token=" + mtoken + "&postBackURL=https://www.jeevaysehat.com/");
Request request = new Request.Builder()
.url("https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf")
.post(body)
.addHeader("content-type", "application/x-www-form-urlencoded")
.addHeader("cache-control", "no-cache")
.build();

Response response = null;
String resp = null;
try {
response = client.newCall(request).execute();
resp = response.body().string();
} catch (Exception e) {
e.printStackTrace();
}

return response.request().url().toString();
}

@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
Log.e("data", s);
//here i redirect to webview activity
Intent ii = new Intent(MainActivity.this, Payment_details.class);
ii.putExtra("data", s);
startActivity(ii);
// Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(s));
// startActivity(browserIntent);

}
}



最佳答案

我已经解决了这个问题并实现了 Telenor easypay API,神奇的是我们将在 webview 中做所有事情......使用 webview 将数据发布到第一个 URL,它将返回附加到 url 的 auth_token 和 postbackurl ......然后发布 auth_token 和postbackurl 到 webview 中的第二个 URL,它将成功地让您进入 easypay 结帐屏幕。

public class Payment_details extends AppCompatActivity {
private WebView webView;
String postData = null;
private RelativeLayout mConfirm;
String data;
boolean isFirst = true;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

setContentView(R.layout.payment_details);
mConfirm = (RelativeLayout) findViewById(R.id.pd_confirm);


webView = (WebView) findViewById(R.id.pdwebView);

data = "https://easypaystg.easypaisa.com.pk/easypay/Index.jsf";
Log.e("data", data);


try {


postData = URLEncoder.encode("amount", "UTF-8")
+ "=" + URLEncoder.encode("10", "UTF-8");

postData += "&" + URLEncoder.encode("storeId", "UTF-8") + "="
+ URLEncoder.encode("xxxx", "UTF-8");

postData += "&" + URLEncoder.encode("postBackURL", "UTF-8")
+ "=" + URLEncoder.encode("your post back url any url", "UTF-8");

postData += "&" + URLEncoder.encode("orderRefNum", "UTF-8")
+ "=" + URLEncoder.encode("1111", "UTF-8");

} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
webView.setWebViewClient(new MyWebViewClient());
WebSettings settings = webView.getSettings();
settings.setJavaScriptEnabled(true);

webView.postUrl(data, postData.getBytes());




}

private class MyWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);


return true;
}

@Override
public void onPageFinished(WebView view, String url) {
super.onPageFinished(view, url);

Log.e("purl", url);
if(isFirst) {
isFirst = false;
String[] ist = url.split("=");
String[] snd = ist[1].split("&");
String Token = snd[0];

Log.e("token", Token);
Log.e("posturl", ist[2]);
secondredirect(Token, view);
}

}

@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
super.onPageStarted(view, url, favicon);




}

@Override
public void onReceivedSslError(WebView view, SslErrorHandler handler, SslError error) {
handler.proceed();
}

}

@Override
public void onBackPressed() {
}

private void secondredirect(String token, WebView view){
String sData = null;
String sURL = "https://easypaystg.easypaisa.com.pk/easypay/Confirm.jsf";
try {
sData = URLEncoder.encode("auth_token", "UTF-8")
+ "=" + URLEncoder.encode(token, "UTF-8");

sData += "&" + URLEncoder.encode("postBackURL", "UTF-8") + "="
+ URLEncoder.encode("any url as a postback url", "UTF-8");
view.postUrl(sURL, sData.getBytes());
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
}
}

关于android - 如何在 Android 中实现 Telenor easypay API,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43002086/

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