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python - 如何移动 pandas 列元素以匹配不同时间的观察结果?

转载 作者:行者123 更新时间:2023-12-03 22:55:10 26 4
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假设我们有以下数据框:

    Date    Type    Country Value
0 2016-04-30 A NL 1
1 2016-04-30 A BE 2
2 2016-04-30 B NL 3
3 2016-04-30 B BE 4
4 2016-04-30 C NL 5
5 2016-04-30 C BE 6
6 2016-04-30 C FR 7
7 2016-04-30 C UK 8
8 2016-05-31 A NL 9
9 2016-05-31 A BE 10
10 2016-05-31 A FR 11
11 2016-05-31 B NL 12
12 2016-05-31 B BE 13
13 2016-05-31 B FR 14
14 2016-05-31 C NL 15
15 2016-05-31 C BE 16
16 2016-05-31 C UK 17
17 2016-05-31 C SL 18
18 2016-06-30 A NL 19
19 2016-06-30 B FR 20
20 2016-06-30 B UK 21
21 2016-06-30 B SL 22
22 2016-06-30 C NL 23
23 2016-06-30 C BE 24

可以使用以下代码计算:

df = pd.DataFrame([['2016-04-30','A','NL',1], ['2016-04-30','A', "BE" ,2], ['2016-04-30', 'B',  'NL',3], ['2016-04-30','B','BE',4], ['2016-04-30','C','NL',5], ['2016-04-30','C','BE',6],['2016-04-30','C','FR', 7], ['2016-04-30','C','UK',8], ['2016-05-31','A','NL',9], ['2016-05-31','A','BE',10], ['2016-05-31','A','FR',11], ['2016-05-31','B','NL',12], ['2016-05-31','B','BE',13], ['2016-05-31','B','FR',14], ['2016-05-31','C','NL',15], ['2016-05-31','C','BE',16], ['2016-05-31','C','UK',17], ['2016-05-31','C','SL',18], ['2016-06-30','A','NL',19], ['2016-06-30','B','FR',20], ['2016-06-30','B','UK',21], ['2016-06-30','B','SL',22], ['2016-06-30','C','NL',23], ['2016-06-30','C','BE',24]], columns=['Date','Type' ,'Country' ,'Value'])

我想添加一个额外的列“ValueShifted”,它基本上可以随时间推移观察值。因此,例如对于观察“日期:2016-05-31,类型:B,国家/地区:BE”,我希望将“ValueShifted”设置为 4。如果观察在前一时期不可用,我会想要将其设置为 NaN。

我可以用蛮力来做到这一点,但这对于我的实际数据集来说会花费太多时间。有没有办法有效地做到这一点?

预期 df:

    Date    Type    Country Value  ValueShifted
0 2016-04-30 A NL 1 nan
1 2016-04-30 A BE 2 nan
2 2016-04-30 B NL 3 nan
3 2016-04-30 B BE 4 nan
4 2016-04-30 C NL 5 nan
5 2016-04-30 C BE 6 nan
6 2016-04-30 C FR 7 nan
7 2016-04-30 C UK 8 nan
8 2016-05-31 A NL 9 1
9 2016-05-31 A BE 10 2
10 2016-05-31 A FR 11 nan
11 2016-05-31 B NL 12 3
12 2016-05-31 B BE 13 4
13 2016-05-31 B FR 14 nan
14 2016-05-31 C NL 15 5
15 2016-05-31 C BE 16 6
16 2016-05-31 C UK 17 8
17 2016-05-31 C SL 18 nan
18 2016-06-30 A NL 19 9
19 2016-06-30 B FR 20 14
20 2016-06-30 B UK 21 nan
21 2016-06-30 B SL 22 nan
22 2016-06-30 C NL 23 15
23 2016-06-30 C BE 24 16

最佳答案

IIUC,你想要GroupBy.shift :

#df['Date']=pd.to_datetime(df['Date'])
#df=df.sort_values(['Date','Type']) #order if necessary
df['ValueShifted']=df.groupby(['Type','Country'])['Value'].shift()
print(df)

输出

         Date Type Country  Value  ValueShifted
0 2016-04-30 A NL 1 NaN
1 2016-04-30 A BE 2 NaN
2 2016-04-30 B NL 3 NaN
3 2016-04-30 B BE 4 NaN
4 2016-04-30 C NL 5 NaN
5 2016-04-30 C BE 6 NaN
6 2016-04-30 C FR 7 NaN
7 2016-04-30 C UK 8 NaN
8 2016-05-31 A NL 9 1.0
9 2016-05-31 A BE 10 2.0
10 2016-05-31 A FR 11 NaN
11 2016-05-31 B NL 12 3.0
12 2016-05-31 B BE 13 4.0
13 2016-05-31 B FR 14 NaN
14 2016-05-31 C NL 15 5.0
15 2016-05-31 C BE 16 6.0
16 2016-05-31 C UK 17 8.0
17 2016-05-31 C SL 18 NaN
18 2016-06-30 A NL 19 9.0
19 2016-06-30 B FR 20 14.0
20 2016-06-30 B UK 21 NaN
21 2016-06-30 B SL 22 NaN
22 2016-06-30 C NL 23 15.0
23 2016-06-30 C BE 24 16.0

关于python - 如何移动 pandas 列元素以匹配不同时间的观察结果?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59377209/

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