去除域名所需的正则表达式

Question

我需要一个正则表达式来去除 url 的域名部分。例如，如果我有以下网址:

http://www.website-2000.com

我希望正则表达式匹配的位是“website-2000”

如果您还可以解释正则表达式的每个部分可以帮助我理解它，那就太好了。

谢谢

Answer 1

这个应该有效。它可能有一些错误，但我现在想不到。如果有人想改进它，请随时这样做。

/http:\/\/(?:www\.)?([a-z0-9\-]+)(?:\.[a-z\.]+[\/]?).*/i

http:\/\/            matches the "http://" part
(?:www\.)?           is a non-capturing group that matches zero or one "www."
([a-z0-9\-]+)        is a capturing group that matches character ranges a-z, 0-9
                     in addition to the hyphen. This is what you wanted to extract.
(?:\.[a-z\.]+[\/]?)  is a non-capturing group that matches the TLD part (i.e. ".com",
                     ".co.uk", etc) in addition to zero or one "/"
.*                   matches the rest of the url

http://rubular.com/r/ROz13NSWBQ