jquery - ajaxForm(options) 什么应该传递给选项？

Question

$(document).ready(function() {
    var options = {
        target: '#output1', // target element(s) to be updated with server response 
        beforeSubmit: showRequest, // pre-submit callback 
        success: showResponse // post-submit callback
    };

    $('#myForm1').ajaxForm(options);
});

function showRequest(formData, jqForm, options) {
    var queryString = $.param(formData);
    alert('About to submit: \n\n' + queryString);
    return true;
}

function showResponse(responseText, statusText) {
    alert('status: ' + statusText + '\n\nresponseText: \n' + responseText +
        '\n\nThe output div should have already been updated with the responseText.');
}

在上面的程序中，选项参数中传递了什么？我使用 http://jquery.malsup.com/

Answer 1

你的问题是什么？

请详细说明。

来自jQuery Form Plugin API Documentation :

ajaxForm

Prepares a form to be submitted via AJAX by adding all of the necessary event listeners. It does not submit the form. Use ajaxForm in your document's ready function to prepare your form(s) for AJAX submission. ajaxForm takes zero or one argument. The single argument can be either a callback function or an Options Object. Chainable: Yes.

Note: You can pass any of the standard $.ajax options to ajaxForm