c++ - 为什么程序在不暂停的情况下关闭？(C++)

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Why does std::getline() skip input after a formatted extraction?

(3个答案)


去年关闭。




我已经编写了一个C++程序来测试复合不等式/等式。

当我在IDE中运行它时，它在关闭之前就停止了，但是当我实际编译并以可执行文件的形式运行时，即使我在末尾特别指定了一行以暂停它，控制台也要关闭才能读取输出。

该代码包括在下面:

#include <iostream>

using namespace std;

int main()
{
    int x;
    int y;
    int a;
    int b;
    int test1;
    int equality;
    int test2;
    bool et1;
    bool lt1;
    bool mt1;
    bool et2;
    bool lt2;
    bool mt2;
    bool t1;
    bool t2;

    cout << "What would you like to do? \n 1) Test two conditions are met \n 2) test if one condition is met out of two \n";
    cin >> equality;

    cout << "what would you like to test for the first pair of numbers? \n 1) if x == y \n 2) if x < y \n 3) if x > y \n";
    cin >> test1;
    cout << "what would you like to test for the second pair of numbers? \n 1) if x == y \n 2) if x < y \n 3) if x > y \n";
    cin >> test2;
    cout << "Choose the first number to the first inequality/equality \n";
    cin >> x;
    cout << "Choose the second number to the first inequality/equality \n";
    cin >> y;
    cout << "Choose the first number to the second inequality/equality \n";
    cin >> a;
    cout << "Choose the second number to the second inequality/equality \n";
    cin >> b;

    if (test1 == 1 && x == y){
        et1 = true;
    }
    else if (test1 == 2 && x < y) {
        lt1 = true;
    }
    else if (test1 == 3 && x > y) {
        mt1 = true;
    }
    else if (test2 == 1 && a == b) {
        et2 = true;
    }
    else if (test2 == 2 && a < b) {
        lt2 = true;
    }
    else if (test2 == 3 && a > b) {
        mt2 = true;
    }

    if (lt1 == true || et1 == true || mt1 == true) {
        t1 = true;
    }

    if (lt2 == true || et2 == true || mt2 == true) {
        t2 = true;
    }

    if (equality = 1 && t1 == true && t2 == true) {
        cout << "this compound and inequality is true";
    }
    else if (equality = 2 ) {
        if (t1 == true || t2 == true) {
            cout << "this compound or inequality is true";
        }
        cout << "this compound inequality is true";
    }

    std::cin.get();
    return 0;
}

最佳答案

您可以包含头文件“conio.h”，并在需要暂停程序时执行getch()调用

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
      cout<<"After printing this there will be a pause.Press any character to contine\n";
      getch();
      cout<<"Code ends\n";
      return(0);
}

关于c++ - 为什么程序在不暂停的情况下关闭？(C++)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58673598/

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Answer 1

您可以包含头文件“conio.h”，并在需要暂停程序时执行getch()调用

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
      cout<<"After printing this there will be a pause.Press any character to contine\n";
      getch();
      cout<<"Code ends\n";
      return(0);
}