sequelize.js - Sequelize : Why Is This $or Not Working?

Question

这有效:

        var args = {fromID: 1, toID: 2};
        var altArgs = {};
        altArgs.fromID = args.toID;
        altArgs.toID = args.fromID;
        var ret = connectors.IM.findAll({ $or: [args, altArgs] }).then((res) => res.map((item) => item.dataValues));

但这不是，即使就 $ 或语法而言，它对我来说看起来完全一样:

        const {fromID, toID} = args;
        var fromArgs = {};
        var toArgs = {};
        fromArgs.userID = fromID;
        toArgs.userID = toID;

        var ret = connectors.myUserData.findAll({ $or: [fromArgs, toArgs] }).then((res) => res.map((item) => item.dataValues));

myUserData 确实包含一个 userID 字段，我要查找的值可以在表中找到。是什么阻止了第二个代码块的工作？

Answer 1

缺少 where Prop :.findAll({where: { $or: [fromArgs, toArgs]}})